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If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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26 Apr 2011, 07:12
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If 7 workers can build 7 cars in 7 days, then how many days would it take 5 workers to build 5 cars? (A) 1 (B) 5 (C) 7 (D) 25 (E) 35
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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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26 Apr 2011, 07:21
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reatsaint wrote: If 7 workers can build 7 cars in 7 days, then how many days would it take 5 workers to build 5 cars?
(A) 1 (B) 5(C) 7(D) 25(E) 35 7 Worker  7 cars  7days 1 Worker 7 cars  7*7 days 1 Worker  1 car  7*7/7=7 days 1 Worker  5 car  7*5 days 5 Worker  5 cars  7*5/5 =7 days Ans: "C"
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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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26 Apr 2011, 07:25
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7w7c7days. 7w1c1day 1w1c7days 1w5c7*5 days 5w5c7*5/5 days= 7days.
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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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26 Apr 2011, 07:27
Thanks Fluke and Jami !!



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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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26 Apr 2011, 08:57
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any of such problem can be solved easily in the following way
Workers cars days 7 7 7 5 5 x We have asked about how many days will require to complete the work
now days are inversely proportional to workers and direct proportional to the cars. When there is inverse proportion take number from the opposite line to X to numerator … and when there is direct proportion take number form the same line to X to numerator … and put other numbers to denominator. Also, take number that is above or below X to numerator or denominator respectively
Hence the equation will be X = 7*5*7 / 5*7 = 7
You can use this method when there are only two related quantities or 100 relaed quantities



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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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26 Apr 2011, 09:09
vyassaptarashi wrote: any of such problem can be solved easily in the following way
Workers cars days 7 7 7 5 5 x We have asked about how many days will require to complete the work
now days are inversely proportional to workers and direct proportional to the cars. When there is inverse proportion take number from the opposite line to X to numerator … and when there is direct proportion take number form the same line to X to numerator … and put other numbers to denominator. Also, take number that is above or below X to numerator or denominator respectively
Hence the equation will be X = 7*5*7 / 5*7 = 7
You can use this method when there are only two related quantities or 100 relaed quantities I was using a method similar to Fluke but made a calculation mistake, and got stuck. That method work easier for me.



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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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26 Apr 2011, 17:43
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reatsaint wrote: If 7 workers can build 7 cars in 7 days, then how many days would it take 5 workers to build 5 cars?
(A) 1 (B) 5(C) 7(D) 25(E) 35
An interesting thing in such questions is 7 workers and 7 cars. Makes me think of each worker working on his own single car and finishing it in 7 days. So 1 worker finishes 1 car in 7 days. 5 workers working on their own individual 5 cars will also take 7 days. 210 workers working on 210 cars will take 7 days too. 210 workers working on 420 cars will take 14 days (each worker makes 1 car in 7 days and then another in another 7 days) and so on... Sometimes you can just reason it out too. reatsaint wrote: I was using a method similar to Fluke but made a calculation mistake, and got stuck. That method work easier for me. Actually, both are using the same concept of variation. You can do it one step at a time or all together, whatever suits you. Just different ways of looking at the same thing. Let me tell you how I think of the all together method. 7 workers  7 cars  7 days 5 workers  5 cars  a days No of days needed = 7 * (5/7) * (7/5) You get this expression by thinking in the following way: Initially, you needed 7 days so that is the quantity that has to change so write "No of days needed = 7 *" Just consider cars now. When you need to make only 5 cars (i.e. less cars) as compared to 7 cars, do you need more days or less? Less ofcourse so you multiply above by (5/7) (it is smaller than 1 so will decrease whatever it multiplies) Now you have: "No of days needed = 7 * (5/7)" Now just consider workers. If you have fewer workers (5 instead of 7), will you need more days to finish the work or less? More ofcourse so multiply by (7/5) (which is greater than 1) Now you have: "No of days needed = 7 * (5/7) * (7/5) = 7 days" On the same lines, try this: 4 people make 28 baskets in 4 days working 8 hrs every day. How many days will 8 people take to make 14 baskets working 2 hrs a day?
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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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26 Apr 2011, 23:33
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VeritasPrepKarishma wrote: On the same lines, try this: 4 people make 28 baskets in 4 days working 8 hrs every day. How many days will 8 people take to make 14 baskets working 2 hrs a day? I recall that I used this formula in 10th grade. Dont know if it is exact  pls verify Man * Days / Work done = constant or Man * Hours / Workdone = constant 4 people * (4 * 8) hrs / 28 baskets = constant = 8 people * (2*D) hrs / 14 baskets D = 4 days Plus there is one more variation of this formula when efficiency of the worker comes into play  Man * Days * efficiency / Work done = constant



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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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27 Apr 2011, 01:07
7 (1car/xday) * 7 days = 7 cars 49/x=7 x=7
Therefore, rate per worker is 1car/7days.
5(1/7)(t)=5cars t=(5)(7/5) t=7days
Answer: 7 days to build 5 cars by 5 workers!



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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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27 Apr 2011, 17:24
gmat1220 wrote: VeritasPrepKarishma wrote: On the same lines, try this: 4 people make 28 baskets in 4 days working 8 hrs every day. How many days will 8 people take to make 14 baskets working 2 hrs a day? I recall that I used this formula in 10th grade. Dont know if it is exact  pls verify Man * Days / Work done = constant or Man * Hours / Workdone = constant 4 people * (4 * 8) hrs / 28 baskets = constant = 8 people * (2*D) hrs / 14 baskets D = 4 days Plus there is one more variation of this formula when efficiency of the worker comes into play  Man * Days * efficiency / Work done = constant Yes, it is correct. The formula is again nothing but application of variation. You say, Man * Days / Work done = constant It implies that 'Man' varies directly with 'Work done' which is obvious since if you need to do more work, you need more men to do it in the same time. Also, 'Man' varies inversely with 'Days' which is again obvious since if you need to do the work in fewer days, you need more men (keeping work done the same) The clubbing of more than two variables is just called 'joint variation'. When you include efficiency, we see that 'man' varies inversely as 'efficiency' which makes sense too. If men are more efficient, you need fewer of them to finish the same work in same time.
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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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11 Aug 2011, 05:38
7 workers  7 days  7cars 5 workers  x days  5cars x = 7*7*5/7*5 = 7 days
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If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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13 Jan 2016, 15:22
7 cars/7 days=1 car per day 1 car/7 workers= 1/7 car per worker per day let d= number of days (5)(1/7)(d)=5 d=7 days



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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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20 Jan 2016, 08:10
I made a silly mistake cause I saw was a low level question and thought "solve it quickly and move on"....and this was the reason why I picked B.
Then, I thought of it and solved in this way:
If 7 workers can build 7 cars in 7 days, also 1 worker can build 7 cars in 49 days and the same worker can build 1 car in 7 days. Multiply it by 5 and you get that 5 workers can build 5 cars in 7 days.
I wanted to use the work=rate*time formula but I had some difficulty. Can someone show me how to solve the problem with that formula please?



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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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20 Jan 2016, 22:28
pepo wrote: I made a silly mistake cause I saw was a low level question and thought "solve it quickly and move on"....and this was the reason why I picked B.
Then, I thought of it and solved in this way:
If 7 workers can build 7 cars in 7 days, also 1 worker can build 7 cars in 49 days and the same worker can build 1 car in 7 days. Multiply it by 5 and you get that 5 workers can build 5 cars in 7 days.
I wanted to use the work=rate*time formula but I had some difficulty. Can someone show me how to solve the problem with that formula please? Yes, you can use that formula too but you have to be careful about the number of workers. In 7 days, 7 cars are made (by 7 workers.) So Work = 7 cars Time = 7 days 7 cars = Rate * 7 days Rate = 1 car/day (assuming 7 workers are working on it) If 5 workers are working on it, rate = (1/7)*5 = 5/7 car/day Time = Work/Rate Time = 5 cars/(5/7) car/day = 7 days I suggest you to look at the variation approach. It will be easier.
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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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21 Jan 2016, 08:34
VeritasPrepKarishma wrote: pepo wrote: I made a silly mistake cause I saw was a low level question and thought "solve it quickly and move on"....and this was the reason why I picked B.
Then, I thought of it and solved in this way:
If 7 workers can build 7 cars in 7 days, also 1 worker can build 7 cars in 49 days and the same worker can build 1 car in 7 days. Multiply it by 5 and you get that 5 workers can build 5 cars in 7 days.
I wanted to use the work=rate*time formula but I had some difficulty. Can someone show me how to solve the problem with that formula please? Yes, you can use that formula too but you have to be careful about the number of workers. In 7 days, 7 cars are made (by 7 workers.) So Work = 7 cars Time = 7 days 7 cars = Rate * 7 days Rate = 1 car/day (assuming 7 workers are working on it) If 5 workers are working on it, rate = (1/7)*5 = 5/7 car/day Time = Work/Rate Time = 5 cars/(5/7) car/day = 7 days I suggest you to look at the variation approach. It will be easier. Thanks for your help. What is the variation approach? Thanks again!



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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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21 Jan 2016, 19:46
pepo wrote: VeritasPrepKarishma wrote: pepo wrote: I made a silly mistake cause I saw was a low level question and thought "solve it quickly and move on"....and this was the reason why I picked B.
Then, I thought of it and solved in this way:
If 7 workers can build 7 cars in 7 days, also 1 worker can build 7 cars in 49 days and the same worker can build 1 car in 7 days. Multiply it by 5 and you get that 5 workers can build 5 cars in 7 days.
I wanted to use the work=rate*time formula but I had some difficulty. Can someone show me how to solve the problem with that formula please? Yes, you can use that formula too but you have to be careful about the number of workers. In 7 days, 7 cars are made (by 7 workers.) So Work = 7 cars Time = 7 days 7 cars = Rate * 7 days Rate = 1 car/day (assuming 7 workers are working on it) If 5 workers are working on it, rate = (1/7)*5 = 5/7 car/day Time = Work/Rate Time = 5 cars/(5/7) car/day = 7 days I suggest you to look at the variation approach. It will be easier. Thanks for your help. What is the variation approach? Thanks again! Check out this post: http://www.veritasprep.com/blog/2015/10 ... madeeasy/Understand the methodology (shown in the first question of the post) and use the same for this question. It will get solved in seconds.
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Re: If 7 workers can build 7 cars in 7 days, then how many days would it [#permalink]
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14 Feb 2016, 02:30
Here is my approach, No. of workers(w) is directly proportional to no. of cars(c) No. of days(d) is also directly proportional to no. of cars(c) But no. of workers(w) is inversely proportional to no. of days(d) So simply put down, the logic becomes d * w = c Per worker effort is 1/7th a car per day Finally d * 5(1/7) = 5, this gives the no. of days for 5 workers to make 5 cars as 7 days. Hope this helps
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