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22 Mar 2026, 19:00
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E
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Difficulty:
15%
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Question Stats:
89% (02:15) correct
11%
(02:37)
wrong
based on 111
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Not Attempted Yet
If a = 15 = b – c, d = bc = –56, e = b^2 + c^2, what is the value of e ?
A. 1
B. 71
C. 86
D. 111
E. 113
A. 1
B. 71
C. 86
D. 111
E. 113
22 Mar 2026, 22:02
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b-c=15 or b=15+c
bc= -56 or (15+c)c= -56
15c+c^2 +56=0 or (c+7)(c+8)=0
c = -7 or -8
If c= -7, b=(-56/-7)=8
If c= -8, b=(-56/-8)=7
e=b^2 +c^2 = 8^2 +(-7)^2 =113
E
bc= -56 or (15+c)c= -56
15c+c^2 +56=0 or (c+7)(c+8)=0
c = -7 or -8
If c= -7, b=(-56/-7)=8
If c= -8, b=(-56/-8)=7
e=b^2 +c^2 = 8^2 +(-7)^2 =113
E
22 Mar 2026, 22:31
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a=15 ;
b-c=15 ; bc=-56 ie., c=-56/b
a=b-c;
substitute c =-56/b in the above eqn
a=b+(56/b)
15b = b^2 +56
factorize to get b = 7 or b = 8
Now substitute b = 7 or 8 in a = b-c
We get c = -8 or -7
Now e = b^2+c^2 (No matter which values you substitute out of (7,-8) or (8,-7) we will get the same value)
= 7^2 + (-8)^2
=113.
Option E
b-c=15 ; bc=-56 ie., c=-56/b
a=b-c;
substitute c =-56/b in the above eqn
a=b+(56/b)
15b = b^2 +56
factorize to get b = 7 or b = 8
Now substitute b = 7 or 8 in a = b-c
We get c = -8 or -7
Now e = b^2+c^2 (No matter which values you substitute out of (7,-8) or (8,-7) we will get the same value)
= 7^2 + (-8)^2
=113.
Option E
