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# If a + 2c = 8, b + 5c = 13, and 3a + 4b= 50, what is the average (arit

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Joined: 02 Sep 2009
Posts: 52168
If a + 2c = 8, b + 5c = 13, and 3a + 4b= 50, what is the average (arit  [#permalink]

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02 Jan 2018, 00:31
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Difficulty:

25% (medium)

Question Stats:

80% (02:34) correct 20% (04:18) wrong based on 85 sessions

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If a + 2c = 8, b + 5c = 13, and 3a + 4b= 50, what is the average (arithmetic mean) of a, b, and c?

A. 3
B. 4
C. 5
D. 6
E. 7

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Re: If a + 2c = 8, b + 5c = 13, and 3a + 4b= 50, what is the average (arit  [#permalink]

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02 Jan 2018, 03:51
Bunuel wrote:
If a + 2c = 8, b + 5c = 13, and 3a + 4b= 50, what is the average (arithmetic mean) of a, b, and c?

A. 3
B. 4
C. 5
D. 6
E. 7

a + 2c = 8 ----> a = 8 - 2c ----->(I)
b + 5c = 13 -----> b = 13 - 5c ------> (II)

Use the values of a & b in 3a + 4b = 50

3 (8 - 2c) + 4 (13 - 5c) = 50

24 - 6c + 52 - 20c = 50

-26c = 50 - 76

c = 1

We can calculate b = 8 & a = 6

Average = $$\frac{(6 + 8 + 1)}{3}$$ = 5

(C)
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Joined: 10 Jun 2018
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Re: If a + 2c = 8, b + 5c = 13, and 3a + 4b= 50, what is the average (arit  [#permalink]

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04 Jan 2019, 20:46

1. a+2c=8
2. b+5c=13
3. 3a+4b=50

Multiply equation 1. by 5 and equation 2. by 2 to cancel out c. After multiplying, equation 1. becomes 5a+10c=40
and equation 2. becomes 2b+10c=26
Subtracting these 2 equations: 5a-2b=14 .........(equation A)
Now we have 2 equations to solve:
A) 5a-2b=14
3. 3a+4b=50

Multiply equation A by 2 to equalize b and then add the two equations to give the value of a. Substitute the value of a in earlier equations to find value of b and c. The values are:
a= 6, b=8, c=1

Mean = (a+b+c)/3 = 15/3= 5
Re: If a + 2c = 8, b + 5c = 13, and 3a + 4b= 50, what is the average (arit &nbs [#permalink] 04 Jan 2019, 20:46
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