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Bunuel
If a^5 ≥ −32 and a is an integer, what is the value of a?

(1) 6a + 18 ≤ 12
(2) a^2 > 2

Asked: If a^5 ≥ −32 and a is an integer, what is the value of a?
a >= -2

(1) 6a + 18 ≤ 12
a + 3 <= 2
a <= -1
-2<=a <=-1
Since a is an integer
a = -2 or a = -1
NOT SUFFICIENT

(2) a^2 > 2
\(-\sqrt{2}<=a<=\sqrt{2}\)
-1.4<=a<=1.4
Since a is an integer >=-2
a = {-1,0,1}
NOT SUFFICIENT

(1) + (2)
(1) 6a + 18 ≤ 12
-2<=a <=-1
a = -2 or a = -1
(2) a^2 > 2
-1.4<=a<=1.4
Since a is an integer >=-2
a = {-1,0,1}
a = -1
SUFFICIENT

IMO C

hi, Kinshook
None of results of Statement2 cannot satisfy the \(a^2 > 2\).
Also, final result -1 does not satisfy the statement2.

Can you check the highlighted part above?
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Kinshook
Bunuel
If a^5 ≥ −32 and a is an integer, what is the value of a?

(1) 6a + 18 ≤ 12
(2) a^2 > 2

Asked: If a^5 ≥ −32 and a is an integer, what is the value of a?
a >= -2

(1) 6a + 18 ≤ 12
a + 3 <= 2
a <= -1
-2<=a <=-1
Since a is an integer
a = -2 or a = -1
NOT SUFFICIENT

(2) a^2 > 2
\(-\sqrt{2}<=a<=\sqrt{2}\)
-1.4<=a<=1.4
Since a is an integer >=-2
a = {-1,0,1}
NOT SUFFICIENT

(1) + (2)
(1) 6a + 18 ≤ 12
-2<=a <=-1
a = -2 or a = -1
(2) a^2 > 2
-1.4<=a<=1.4
Since a is an integer >=-2
a = {-1,0,1}
a = -1
SUFFICIENT

IMO C

hi, Kinshook
None of results of Statement2 cannot satisfy the \(a^2 > 2\).
Also, final result -1 does not satisfy the statement2.

Can you check the highlighted part above?

Corrected. Thanks
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Bunuel
If a^5 ≥ −32 and a is an integer, what is the value of a?

(1) 6a + 18 ≤ 12
(2) a^2 > 2

From the stem, we can infer that, a >= -2.

1) 6a <= -6, so a <= -1, a can be either -1 or -2. not sufficient.

2) The square root of any integer more than 1 is at least slightly more than 1. So, here a is less than -1. We can ignore positive values as a is a negative integer. So, a can assume only the value of -2. Sufficient.
B is the answer.
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