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# If A = 7x/5y, with y ≠ 0, what is the value of A?

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Joined: 02 Sep 2009
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If A = 7x/5y, with y ≠ 0, what is the value of A?  [#permalink]

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26 Mar 2018, 23:05
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Difficulty:

15% (low)

Question Stats:

97% (00:51) correct 3% (01:12) wrong based on 44 sessions

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If A = 7x/5y, with y ≠ 0, what is the value of A?

(1) x = 10y
(2) x = 5/7

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Re: If A = 7x/5y, with y ≠ 0, what is the value of A?  [#permalink]

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27 Mar 2018, 00:52
Bunuel wrote:
If A = 7x/5y, with y ≠ 0, what is the value of A?

(1) x = 10y
(2) x = 5/7

This is a simple Q.

$$A = \frac{7x}{5y}$$ and we need to find A.

(1) x = 10y. If we substitute the value of x, the y cancels out (note y ≠ 0 is given! and we can find A. Sufficient.

(2) x = 5/7 when substituted leaves y which is a variable in the result. Hence A is not determined. Insufficient.

Hence Option (A) is correct
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Re: If A = 7x/5y, with y ≠ 0, what is the value of A?  [#permalink]

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02 Apr 2018, 13:56
I personally analyzed first that we have two variables in the question. To determine the value we need to eliminate both variables. Hence, we need a statement or a combination of statements that eliminates these two variables.

Statement (1) does exactly that by substituting x with 10y. This allows us to cancel out y because we have y in the numerator and denominator of the fracttion.

Statement (2) leaves us with y in the denominator and hence doesn't solve the question.

In conclusion, answer A is correct
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Re: If A = 7x/5y, with y ≠ 0, what is the value of A?   [#permalink] 02 Apr 2018, 13:56
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# If A = 7x/5y, with y ≠ 0, what is the value of A?

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