If a and b are integers, and |a| |b|, is a |b|

Question

If a and b are integers, and |a| > |b|, is a · |b| = 0

asterixmatrix · Answer

1. a< 0 . We know that |b|> =0 if b is +/- any number or 0 lets consider a = -2 and b = 0 then we get -2 · 0 < -2 -0 which is incorrect lets consider a = -2 and b = -3 then we get -2·|-3|< -2 - (-3) which is correct. Hence A is insuff 2. ab >= 0 for ab =0 b will be 0 as we have |a| > |b| now if b =0 and a =-2 then -2· |0| < -2 -0 which is incorrect now if b = 3 and a = 4 then ab = 12 and 4· 3< 4-3 is incorrect now if b = 10 and a = -2 then -2·10< -2 -10 which is correct hence insuff now consider both a<0 and ab >=0 , for this we can have b =0 and -ve if a=-2 and b= 0 then a<0,ab=0 and -2·0< -2-0 which is incorrect if a = -2 and b = -3 then a<0, ab>0 and -2.3 < -2 - (-3) which is correct Hence insuff. Ans E

yangsta8 · Answer

Hey hogann - I asked the same thing a week ago. More here: absolute-values-85086.html

pittgreek · Answer

E . Take 2 numbers like a = -1 and B -4 .. that will solve the solution

If a and b are integers, and |a| > |b|, is a |b| < a

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