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If a and b are nonzero, does the point (a,b) lie in the quadrant II of

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If a and b are nonzero, does the point (a,b) lie in the quadrant II of  [#permalink]

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New post 14 Aug 2016, 11:04
2
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A
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C
D
E

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If a and b are nonzero, does the point (a,b) lie in the quadrant II of the xy plane?

1) a = -b
2) a < 0

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Senior Manager
Senior Manager
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Joined: 23 Apr 2015
Posts: 295
Location: United States
Concentration: General Management, International Business
WE: Engineering (Consulting)
Re: If a and b are nonzero, does the point (a,b) lie in the quadrant II of  [#permalink]

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New post 14 Aug 2016, 11:43
1
1) a = -b
(a,b) can be in II or IV, so not sufficient, eliminate A and D

2) a < 0
(a,b) can be in III or IV, so not sufficient , eliminate B,

consider 1) and 2), (a,b) will be in IV, so sufficient,

Therefore C is the answer.



+1 Kudos :)
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Re: If a and b are nonzero, does the point (a,b) lie in the quadrant II of  [#permalink]

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New post 14 Aug 2016, 13:43
Hi Senthil1981,

My question is, how do you come to conclusion from the st1 that (a,b) can be in II or IV? Do you take -b and put the value in the original question points which will become (-b,b) Or what? Its super basic but I'm confused here.

Thanks for your help!


Senthil1981 wrote:
1) a = -b
(a,b) can be in II or IV, so not sufficient, eliminate A and D

2) a < 0
(a,b) can be in III or IV, so not sufficient , eliminate B,

consider 1) and 2), (a,b) will be in IV, so sufficient,

Therefore C is the answer.



+1 Kudos :)
Senior Manager
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Location: United States
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Re: If a and b are nonzero, does the point (a,b) lie in the quadrant II of  [#permalink]

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New post 14 Aug 2016, 14:53
HarveyKlaus wrote:
Hi Senthil1981,

My question is, how do you come to conclusion from the st1 that (a,b) can be in II or IV? Do you take -b and put the value in the original question points which will become (-b,b) Or what? Its super basic but I'm confused here.

Thanks for your help!


Hi HarveyKlaus,
if a = -b, as per statement 1, then it means, X and Y have opposite signs, one of them is positive and other is negative.
And of the 4 quadrants only in II and IV, the X and Y will have opposite signs. Just imagine any value for X and as per this condition,
y will be equal to -X, and the point (x,y) will be in either II or IV quadrant.

Quote:
Senthil1981 wrote:
1) a = -b
(a,b) can be in II or IV, so not sufficient, eliminate A and D

2) a < 0
(a,b) can be in III or IV, so not sufficient , eliminate B,

consider 1) and 2), (a,b) will be in IV, so sufficient,

Therefore C is the answer.



+1 Kudos :)
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Re: If a and b are nonzero, does the point (a,b) lie in the quadrant II of  [#permalink]

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New post 24 Feb 2019, 14:49
Yes, it is in the quadrant II once a<0 and a and b have opposite signs... a is neg, b is pos. Quadrant II
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Re: If a and b are nonzero, does the point (a,b) lie in the quadrant II of   [#permalink] 24 Feb 2019, 14:49
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