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21 Feb 2018, 23:09
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E
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Difficulty:
5%
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Question Stats:
93% (00:43) correct
7%
(01:03)
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based on 117
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If a and b are positive integers and \(a^3b^2 = 72\), then a + b =
(A) 36
(B) 17
(C) 8
(D) 6
(E) 5
(A) 36
(B) 17
(C) 8
(D) 6
(E) 5
21 Feb 2018, 23:14
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Factors of 72 are: \(2^3\)*\(3^2\)
So \(a^3\)\(b^2\)= \(2^3\)*\(3^2\)
So a= 2 and b=3
a + b= 5
Answer: E.
So \(a^3\)\(b^2\)= \(2^3\)*\(3^2\)
So a= 2 and b=3
a + b= 5
Answer: E.
Mo2men
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22 Feb 2018, 03:07
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Bunuel
If a and b are positive integers and \(a^3b^2 = 72\), then a + b =
(A) 36
(B) 17
(C) 8
(D) 6
(E) 5
(A) 36
(B) 17
(C) 8
(D) 6
(E) 5
Prime factorization
\(a^3b^2 = 72\) = \(2^3 3^2\)
a +b = 2+3 =5
Answer: E
