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For a moment i was about to mark C
then realised that 10 *10 which is the least value of A^2 will be divisible by 20
hence choose A
nice question
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pushkarajnjadhav
If a and b are positive integers, is 3*a^2*b divisible by 60?

1) a is divisible by 10.
2) b is divisible by 18.

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Is \(3a^2b\) divisible by 60?
- We can change 60 into \(2^2*3*5\).
- Because we already have 3 in the numerator, so our job is to make sure whether a or b has \(2^2\) and 5 as its factor.

#1
- a divisible by 10 or \(2^5\). Since our numerator change a into \(a^2\), so we MUST HAVE \(2^2*5^2\) in our numerator.
- Whatever value of b, \(3a^2b\) divisible by 60.
SUFFICIENT.

#2
- b divisible by 18 or \(2*3^2\), Since we still need to have 5 as factor, we do not know whether a have this factor.
- Divisibility of \(3a^2b\) by 60 depends solely on the a value - which we don't know here.
INSUFFICIENT.

A.
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