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23 Feb 2026, 20:00
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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86% (01:29) correct
14%
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based on 87
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If ‘A’ and ‘B’ denote positive integers, which of the following cannot be a value of the difference between the two-digit integers ‘AB’ and ‘BA’ ?
A. 18
B. 27
C. 29
D. 45
E. 72
A. 18
B. 27
C. 29
D. 45
E. 72
23 Feb 2026, 22:08
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10x+y - [10y+x] = 9(x-y)
Therefore, answer is divisible by 9
29 is NOT divisible by 9 already so that is our answer.
Answer: Option C
=================================================================
Now it is important to note that ANY number divisible by 9 wont be valid that is to say here that
IF 99 were in the options it WONT be a difference in value because x-y can never by 11 (9*11=99)
Max value of x-y = 9 therefore all multiples of 9 from 9 to 81 is possible
Therefore, answer is divisible by 9
29 is NOT divisible by 9 already so that is our answer.
Answer: Option C
=================================================================
Now it is important to note that ANY number divisible by 9 wont be valid that is to say here that
IF 99 were in the options it WONT be a difference in value because x-y can never by 11 (9*11=99)
Max value of x-y = 9 therefore all multiples of 9 from 9 to 81 is possible
ExpertsGlobal5
24 Feb 2026, 03:44
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ExpertsGlobal5
A positive integer AB can be represented as 10A + B
Similarly, the term BA can be represented as 10B+A
The use of 10 is the denote the tens digit. For example 32 can be written as 3*10 + 2.
When we subtract both we get, 10A + B - (10B+A) = 9A - 9B
= 9*(A-B)
The answer is a MULTIPLE OF 9.
Among the Option C = 29 is not a multiple of 9.
