Bunuel
If a < b < 0, which of the following must be true?
A. a^2 < b^2
B. b − 10 < a
C. b + a > a
D. ab < b^2
E. ab < a^2
Kudos for a correct solution. VERITAS PREP OFFICIAL SOLUTION:E. In this problem you should see that a and b are both negative numbers, and that a has a greater absolute value (it's further from zero) than b does. So when you square a, you'll end up with a larger positive number than when you multiply a by a lesser-absolute-value b. So choice E must be true. Choosing numbers can help exemplify:
a = -10, b = -5
Would mean that a^2 = 100 and ab = 50, so a^2 is bigger.
Even if you try with fractions (always a good idea to consider), a = -3/4 and b = -1/2 yields:
a^2 = 9/16 (greater than 1/2)
ab = 3/8 (less than 1/2)
Proving E to be true. For the incorrect answers:
A) Since a has a larger absolute value, when it's squared it will be larger than b-squared.
B) Because you don't know the relative values of a and b, you can't determine that moving b 10 places to the left will reduce it past a.
C) Adding a negative number (b) to a will make it smaller, not larger, than the original a.
D) See demonstration above.