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Updated on: 29 Jan 2020, 23:51
Originally posted by QuantMadeEasy on 29 Jan 2020, 22:18.
Last edited by Bunuel on 29 Jan 2020, 23:51, edited 1 time in total.
Last edited by Bunuel on 29 Jan 2020, 23:51, edited 1 time in total.
Renamed the topic, edited the question and edited the tags.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
44% (01:02) correct
56%
(00:55)
wrong
based on 75
sessions
History
Date
Time
Result
Not Attempted Yet
If \(a\sqrt{b}=c\), what is the value of b?
(1) \(b^2 = 81\)
(2) \(\frac{c}{a} = 3\)
(1) \(b^2 = 81\)
(2) \(\frac{c}{a} = 3\)
30 Jan 2020, 07:48
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It's clear that whoever wrote this question is trying to be 'tricky' by not telling you that b is positive, but by including "√b" in the problem, which is only defined if b is positive (or zero). That's what makes Statement 1 have only one solution (and Statement 2 is clearly sufficient alone) so the answer is D.
But if a question is going to include the expression √b, the question needs to tell you explicitly that b is positive (or zero), since a GMAT question can't present you with potentially undefined expressions. So the 'trick' the question designer is trying to use here is one you'd never see on the actual test. What is the source?
But if a question is going to include the expression √b, the question needs to tell you explicitly that b is positive (or zero), since a GMAT question can't present you with potentially undefined expressions. So the 'trick' the question designer is trying to use here is one you'd never see on the actual test. What is the source?
02 Dec 2023, 07:33
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Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
