kostyan5 wrote:

If \(a+b=200\) and \(a<b\), is \(a+b>c+d\)?

(1) \(c+d<200\)

(2) \(b+c+d=300\)

\(a+b=200\) and \(a<b\)

Thus, \(a + b < 2b\)

Or, \(200 < 2b\)

Or, \(b > 100\)

FROM STATEMENT - I ( SUFFICIENT ) Given , \(a+b=200\) & \(c+d<200\)

Thus, we can safely conclude - \(a+b>c+d\)

FROM STATEMENT - II ( SUFFICIENT )

I will try to plug in some value and check here, \(a+b=200\) & \(b > 100\)

Say \(b = 110\) & \(a = 90\)

Given, \(b+c+d=300\) , if \(b = 110\) , \(c + d = 190\)

It is given, \(a+b=200\) & we have \(c + d = 190\)

So, we can safely conclude here as well that \(a+b>c+d\)

Thus, EACH statement ALONE is sufficient to answer the question asked, answer will be (D)
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Thanks and Regards

Abhishek....

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