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If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

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If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 09 Feb 2017, 05:01
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 12 Feb 2017, 05:47
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1
Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5



Hey,

Though there are a number of ways to solve this. I would like to use a slightly different method which involved options elimination, using the concept of even-odd.

We are given that a+b = 2c, now 2c is EVEN, therefore the sum of a + b should also be EVEN.

Look at the answer choices and focus on only the first two numbers and their sum -

    A. \(1+2 = 3\) - ODD
    B. \(1 + 3 = 4\)- EVEN
    C. \(3+ 2 = 5\) - ODD
    D. \(1+ 4 =5\) - ODD
    E.\(1+2 =3\) - ODD

Hence Option B is the correct answer. :)

It is always a good idea to look for patterns in the options if one is not sure how to approach using the conventional method. :)

Thanks,
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 09 Feb 2017, 05:42
3
add c on both side:
a+b+c = 3c
a+5a=3c
6a=3c
2a=c

from substitue:

a+2a=b
3a=b

so ratio will be 1:3:2

answer b
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 09 Feb 2017, 07:31
1
giobas wrote:
add c on both side:
a+b+c = 3c
a+5a=3c
6a=3c
2a=c

from substitue:

a+2a=b
3a=b

so ratio will be 1:3:2

answer b


Nice way of solving it.. I couldn't. I had to back test the options one by one
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 09 Feb 2017, 08:17
JamieCecil wrote:
Nice way of solving it.. I couldn't. I had to back test the options one by one


I will consider that as an effective way of solving this question , I do the same as well...

Check using the options..

For option (B) -

a = 1
b = 3
c = 2

a + b = 2c Or, 1 + 3 = 2*2 ( Satisfies )
a + c = b , Or, 1 + 2 = 3 ( Satisfies )
b + c = 5a, Or 3 + 2 = 5*1 ( Satisfies )

Check using other options, none except (B) satisfies, hence thats the correct answer...

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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 12 Feb 2017, 01:52
in such kind of problems its easy to back solving it if we plug answers then the only values which satisfy is 1:3:2 which option B
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 12 Feb 2017, 13:12
Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5


I think the sum can be solved just by scanning the options.

Given a+c =b, two inferences can be made from this option.
1. If all three numbers are negative, b has to be the smallest. None of the ratios in the options have b as the smallest. So the numbers are positive.
2. Since the numbers are positive, b is the largest among a,b, and c. So options A,C, and E can be eliminated as b is not the biggest in them.

Option D says the b is twice that of c. If that's the case then from 1st equation a=2c-b will be 0 so the ratio will fall.

Hence B is the answer.
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 13 Feb 2017, 15:59
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Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5


We are given that:

a + b = 2c

a + c = b

b + c = 5a

Subtracting the second equation from the first equation, we have:

(a + b = 2c) - (a + c = b)

b - c = 2c - b

2b = 3c

Subtracting the third equation from the second equation, we have:

(a + c = b) - (b + c = 5a)

a - b = b - 5a

6a = 2b

Since 2b = 3c and 2b = 6a, we can say that 6a = 2b = 3c

Furthermore, we see that 6a = 2b = 3c holds when a = 1, b = 3, and c = 2.

Thus, the ratio of a to b to c = 1 to 3 to 2.

Answer: B
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 18 Apr 2017, 01:33
Option B

Correct ratio should give a + b as Even (Using eq.n I)

"Alternatively"

Correct ratio should satisfy all 3 equations.

E.g., a + b =2c : 1+3 = 2*2 For B).
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 23 Apr 2017, 19:29
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Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5


You don't necessarily even have to substitute- just plug in a value for a b and c that works and then you have a ratio; for example, consider a = 1, b = 3 , c = 2

1 + 3 = 2(2)

Albeit, it is still important to know how to substitute values into equations which I think is the concept being tested. Learn the rules only to break them when convenient.
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If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post Updated on: 25 Apr 2017, 05:32
1
Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5


a+c=b gives the answer away without any math.
This means that b is largest.
The only answers with b being the largest are B & D.
Looking at B you can cleary see that 1+2=3 or a+c=b

Originally posted by IdiomSavant on 24 Apr 2017, 12:23.
Last edited by IdiomSavant on 25 Apr 2017, 05:32, edited 2 times in total.
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 24 Apr 2017, 15:49
IdiomSavant wrote:
Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5


a+c=b gives the answer away without any math.
This means that b is largest.
The only answers with b being the largest are B & D.
Looking at B you can clear see that 1&2=3 or a+c=b


That's kind what I thought too
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 27 May 2017, 05:39
Abhishek009 : I tried solving it the traditional way and it took me a considerable amount of time. I liked your method of plugging in nos. from the options given. I wanted to check if it will be fairly OK to just check any one of the three equations as long as only one option gives positive result for that equation and move on without checking the answer choices for the remaining equations ?
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 27 May 2017, 14:56
Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5


Here, I used only two of the three equations, avoiding b + c = 5a entirely.

b is the only variable with coefficient 1 in all three equations.

1. With b as initial focus, rewrite a + c = b ----> b = a + c

2. Two equations to choose from now: a + b = 2c and b + c = 5a.

Coefficient 2 looked easier than coefficient 5. So I substituted value of b into a + b = 2c ---->

a + (a + c) = 2c, subtract c from both sides to get

2a = c or c = 2a

3. c now has a coefficient of 1, and b has a coefficient of 1 in equation from Step 1: b = a + c, substitute c = 2a ------> b = a + 2a, b = 3a

4. b and c are now both written in terms of a, thus

a = 1a
b = 3a
c = 2a.

Ratio of a:b:c is therefore 1:3:2

Answer B
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 24 Jun 2017, 05:51
My solution is as follows:

try to see the equations and find out which is the largest among a, b, c; clearly by equation 2 we can say b is the largest.
only two options have b as the largest, plug one into the the set of equations, if it passes great! else the other is the answer.!
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If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 06 Jul 2020, 16:39
EgmatQuantExpert wrote:
Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5



Hey,

Though there are a number of ways to solve this. I would like to use a slightly different method which involved options elimination, using the concept of even-odd.

We are given that a+b = 2c, now 2c is EVEN, therefore the sum of a + b should also be EVEN.

Look at the answer choices and focus on only the first two numbers and their sum -

    A. \(1+2 = 3\) - ODD
    B. \(1 + 3 = 4\)- EVEN
    C. \(3+ 2 = 5\) - ODD
    D. \(1+ 4 =5\) - ODD
    E.\(1+2 =3\) - ODD

Hence Option B is the correct answer. :)

It is always a good idea to look for patterns in the options if one is not sure how to approach using the conventional method. :)

Thanks,
Saquib
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Hello EgmatQuantExpert Bunuel - follow up on this method of doing the problem VeritasKarishma

I understand a + b has to be an even multiple of 2

Question : in all the answer choices, its quite possible that the unknown multiplier in all the options are even

Option 1) is 1: 2 :3

Assuming an even multiplier, lets say k = 6, thus the actual values are 6 : 12 : 18

Hence a + b in this ratio is also even (i.e. 6 + 12 = 18)

Why is this not a scenario / option we need to look at.

Thank you !
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?  [#permalink]

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New post 09 Jul 2020, 23:19
jabhatta@umail.iu.edu wrote:
EgmatQuantExpert wrote:
Bunuel wrote:
If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

A. 1:2:3
B. 1:3:2
C. 3:2:1
D. 1:4:2
E. 1:2:5



Hey,

Though there are a number of ways to solve this. I would like to use a slightly different method which involved options elimination, using the concept of even-odd.

We are given that a+b = 2c, now 2c is EVEN, therefore the sum of a + b should also be EVEN.

Look at the answer choices and focus on only the first two numbers and their sum -

    A. \(1+2 = 3\) - ODD
    B. \(1 + 3 = 4\)- EVEN
    C. \(3+ 2 = 5\) - ODD
    D. \(1+ 4 =5\) - ODD
    E.\(1+2 =3\) - ODD

Hence Option B is the correct answer. :)

It is always a good idea to look for patterns in the options if one is not sure how to approach using the conventional method. :)

Thanks,
Saquib
Quant Expert
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Hello EgmatQuantExpert Bunuel - follow up on this method of doing the problem VeritasKarishma

I understand a + b has to be an even multiple of 2

Question : in all the answer choices, its quite possible that the unknown multiplier in all the options are even

Option 1) is 1: 2 :3

Assuming an even multiplier, lets say k = 6, thus the actual values are 6 : 12 : 18

Hence a + b in this ratio is also even (i.e. 6 + 12 = 18)

Why is this not a scenario / option we need to look at.

Thank you !


Yes, you are right. If the multiplier is even, though the sum of ratio terms may not be even, the actual sum may be even.
Instead I would use the knowledge that the addition relation of actual variables holds in case of ratios too.
i.e. if actually a + b = 2c, then even in ratio terms, a + b will be equal to 2c.

Since 1 + 2 is not equal to 2*3, this is not correct.

Only for option (B), 1 + 3 = 2*2

Note why this is so. We routinely use the ratio scale and actual value scale while using ratios as discussed here:
https://www.veritasprep.com/blog/2011/0 ... of-ratios/

Let's say we have the ratio a:b:c = 1:3:2
Then, a = k, b = 3k and c = 2k

Then an addition relation such as a + b = 2c becomes
k + 3k = 2 * 2k
k(1 + 3) = 2 * 2k
(1 + 3) = 2*2

Since we can take the common multiplier out, the same relation will hold in terms of ratios too.
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Re: If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?   [#permalink] 09 Jul 2020, 23:19

If a+b=2c, a+c=b, and b+c=5a, what is the ratio of a:b:c?

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