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If (a+b)/(a-b)=55/17 then what is a/b=?

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If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post Updated on: 07 Dec 2014, 05:21
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If \(\frac{(a+b)}{(a-b)}=\frac{55}{17}\) then what is \(\frac{a}{b}\) ?

A) \(\frac{13}{17}\)

B) \(\frac{36}{19}\)

C) \(\frac{19}{7}\)

D) \(\frac{3}{2}\)

E) \(\frac{43}{17}\)

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Originally posted by kukr007 on 06 Dec 2014, 10:32.
Last edited by Bunuel on 07 Dec 2014, 05:21, edited 1 time in total.
Edited the question.
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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 07 Dec 2014, 01:48
\(\frac{(a+b)}{(a-b)}\)=\(\frac{55}{17}\)
dividing numerator and denominator of left hand side by b,we get
\(\frac{([fraction](a}{b)}+1)/(\frac{(a}{b)}-1)[/fraction]\)=\(\frac{55}{17}\)
let a/b be x we have
\(\frac{(x+1)}{(x-1)}\)=\(\frac{55}{17}\)
=> 17*(x+1) = 55*(x-1)
Solving this we get
x = 72/38
x = a/b = 72/38 = 36/19

So, Answer will be B
hope it helps!

kukr007 wrote:
if \(\frac{(a+b)}{(a-b)}\)=\(\frac{55}{17}\) then what is \(\frac{a}{b}\)=?

A) \(\frac{13}{17}\)

B) \(\frac{36}{19}\)

C) \(\frac{19}{7}\)

D) \(\frac{3}{2}\)

E) \(\frac{43}{17}\)

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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 07 Dec 2014, 05:23
1
kukr007 wrote:
If \(\frac{(a+b)}{(a-b)}=\frac{55}{17}\) then what is \(\frac{a}{b}\) ?

A) \(\frac{13}{17}\)

B) \(\frac{36}{19}\)

C) \(\frac{19}{7}\)

D) \(\frac{3}{2}\)

E) \(\frac{43}{17}\)


\(\frac{(a+b)}{(a-b)}=\frac{55}{17}\);

Cross-multiply: \(17a+17b=55a-55b\) --> \(38a=72b\) --> \(\frac{a}{b}=\frac{72}{38}=\frac{36}{19}\).

Answer: B.
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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 08 Dec 2014, 18:53
Let....

a + b = 55x .............. (1)

a - b = 17x ............... (2)

=======================

2a = 72x

a = 36x

b = 55x - 36x = 19x

\(\frac{a}{b} = \frac{36}{19}\)

Answer = B
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If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 09 Dec 2014, 01:44
kukr007 wrote:
If \(\frac{(a+b)}{(a-b)}=\frac{55}{17}\) then what is \(\frac{a}{b}\) ?

A) \(\frac{13}{17}\)

B) \(\frac{36}{19}\)

C) \(\frac{19}{7}\)

D) \(\frac{3}{2}\)

E) \(\frac{43}{17}\)



Only in B 36+19=55 and 36-19=17

B
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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 09 Dec 2014, 03:32
kukr007 wrote:
If \(\frac{(a+b)}{(a-b)}=\frac{55}{17}\) then what is \(\frac{a}{b}\) ?

A) \(\frac{13}{17}\)

B) \(\frac{36}{19}\)

C) \(\frac{19}{7}\)

D) \(\frac{3}{2}\)

E) \(\frac{43}{17}\)


a+b=55
a-b=17

Adding the 2 equation,we get 2a=72,a =36 and b=36-17=19
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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 09 Dec 2014, 05:51
Options are in the form of a/b so according to the question the sum of numerator and denominator(a+b=55) should be equal to 55. The only option satisfying the condition is B 36+19=55.
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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 28 Oct 2017, 07:04
Hi, is this a correct method to solve:

(A+B) + (A-B) = 55 + 17
2A = 72
A=36
Therefore B = 19
?
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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 28 Oct 2017, 20:19
3
(a+b)/(a-b)= 55/17
Now using Componendo & Dividendo
(a+b+a-b)/(a+b-a+b) = (55+17)/(55-17)
2a/2b =72/38
a/b= 36/19

Answer B

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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 10 Nov 2017, 20:38
I feel this is one of the best method and also the old skool concept...
No need to find a & b separately.

frndrobinster wrote:
(a+b)/(a-b)= 55/17
Now using Componendo & Dividendo
(a+b+a-b)/(a+b-a+b) = (55+17)/(55-17)
2a/2b =72/38
a/b= 36/19

Answer B

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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 11 Nov 2017, 00:11
a+b = 55x
a-b = 17x

So 2a = 72
a = 36
So answer B
so answer should be
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Re: If (a+b)/(a-b)=55/17 then what is a/b=?  [#permalink]

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New post 11 Nov 2017, 08:52
kukr007 wrote:
If \(\frac{(a+b)}{(a-b)}=\frac{55}{17}\) then what is \(\frac{a}{b}\) ?

A) \(\frac{13}{17}\)

B) \(\frac{36}{19}\)

C) \(\frac{19}{7}\)

D) \(\frac{3}{2}\)

E) \(\frac{43}{17}\)

\(2a = 72\)

So, \(a = 36\)

Now, a + b = 55

So, 36 + b = 55

Or, \(b = 19\)

Hence, \(\frac{a}{b} = \frac{36}{19}\) , answer will be (B)
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Re: If (a+b)/(a-b)=55/17 then what is a/b=? &nbs [#permalink] 11 Nov 2017, 08:52
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