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Re: If (a+b)/(a-b)=55/17 then what is a/b=?
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07 Dec 2014, 01:48

\(\frac{(a+b)}{(a-b)}\)=\(\frac{55}{17}\) dividing numerator and denominator of left hand side by b,we get \(\frac{([fraction](a}{b)}+1)/(\frac{(a}{b)}-1)[/fraction]\)=\(\frac{55}{17}\) let a/b be x we have \(\frac{(x+1)}{(x-1)}\)=\(\frac{55}{17}\) => 17*(x+1) = 55*(x-1) Solving this we get x = 72/38 x = a/b = 72/38 = 36/19

So, Answer will be B hope it helps!

kukr007 wrote:

if \(\frac{(a+b)}{(a-b)}\)=\(\frac{55}{17}\) then what is \(\frac{a}{b}\)=?

Re: If (a+b)/(a-b)=55/17 then what is a/b=?
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09 Dec 2014, 05:51

Options are in the form of a/b so according to the question the sum of numerator and denominator(a+b=55) should be equal to 55. The only option satisfying the condition is B 36+19=55.