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Re: If a, b and c are integers, is ab a multiple of 18? [#permalink]
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From statement 1
b is mult of 2
a is mult of 3

insufficient: a*b could be 6 or 18 or other numbers

From statement 2
c is mult of 2
b is mult of 3

insufficient: we don't know anything about a

Combined: statements 1 and 2 give us that b is a multiple of both 2 and 3 (ie mult of 6) and a is a multiple of 3: a*b is minimum a multiple of 18
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Re: If a, b and c are integers, is ab a multiple of 18? [#permalink]
what about zero? C because b=0 a=0 hence no we can answer ! answer c
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Re: If a, b and c are integers, is ab a multiple of 18? [#permalink]
Taking first statement 2a=3b , a = 3/2 b so b must be multiple of 2 say 2m .a=3m, ab=6m^2 so it depends on value of m to decide if ab is multiple of 18 or not . A is not the answer . Similarly 2b=3c b=3/2c c must be multiple of 2 say c=2p ab = 6p condition can't be determined . B is not the answer .
Now taking both sentence together a= 3/2b let b=2n ,a will be 3n.second statement gives 4n=3c ,c=4/3n as c is integerer so n must be multiple of 3 , n= 3t .a now becomes 6t and b 9t clearly ab is 54t^2 so it is multiple of 18

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Re: If a, b and c are integers, is ab a multiple of 18? [#permalink]
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