|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
02 May 2019, 23:58
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:24) correct
19%
(01:59)
wrong
based on 68
sessions
History
Date
Time
Result
Not Attempted Yet
If a, b and c are positive integers and a and b are odd, then\(3^a + (b − 1)^2 c\) is
(A) odd for all choices of c
(B) even for all choices of c
(C) odd, if c is even; even, if c is odd
(D) odd, if c is odd; even, if c is even
(E) odd, if c is not a multiple of 3; even if c is a multiple of 3
(A) odd for all choices of c
(B) even for all choices of c
(C) odd, if c is even; even, if c is odd
(D) odd, if c is odd; even, if c is even
(E) odd, if c is not a multiple of 3; even if c is a multiple of 3
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
03 May 2019, 01:27
Kudos
Bookmarks
3^a always odd
B-1 always even ^2 always even
C- doesn't really matter coz when mulitply with even number its always be even
So it's odd+even = always odd
Posted from my mobile device
B-1 always even ^2 always even
C- doesn't really matter coz when mulitply with even number its always be even
So it's odd+even = always odd
Posted from my mobile device
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
