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Re: If a, b, c, and d are consecutive integers and a < b < c < d, what is [#permalink]
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22 Jan 2018, 08:36
Bunuel wrote:
If a, b, c, and d are consecutive integers and a < b < c < d, what is the average (arithmetic mean) of a, b, c, and d in terms of d?
(A) d – 5/2
(B) d – 2
(C) d – 3/2
(D) d + 3/2
(E) (4d – 6)/7
As the numbers are consecutive, let the numbers be c-2, c-1,c , c+1 A.M = (4c-2)/4 = c -(1/2).. Also, as d = c+1 from above equation, c = d - 1 So, AM = d -(3/2)
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Re: If a, b, c, and d are consecutive integers and a < b < c < d, what is [#permalink]
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22 Jan 2018, 23:29
1. Av= \(\frac{(A+D)}{2}\) (as it is consecutive evenly spaced numbers) 2. Range = D-A=3 (as it is consecutive numbers with increment of 1) 3. Substitute A= D-3 in 1. Av=\(\frac{(D-3+D)}{2}\) ->Av=\(\frac{(2D-3)}{2}\) 4. After dividing by 2 it becomes Av=D-\(\frac{3}{2}\). Answer (C)
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85% (01:03) correct 
