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22 Jan 2018, 01:54
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (01:27) correct
20%
(01:40)
wrong
based on 366
sessions
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If a, b, c, and d are consecutive integers and a < b < c < d, what is the average (arithmetic mean) of a, b, c, and d in terms of d?
(A) \(d - \frac{5}{2}\)
(B) \(d - 2\)
(C) \(d - \frac{3}{2}\)
(D) \(d + \frac{3}{2}\)
(E) \(\frac{4d-6}{7}\)
(A) \(d - \frac{5}{2}\)
(B) \(d - 2\)
(C) \(d - \frac{3}{2}\)
(D) \(d + \frac{3}{2}\)
(E) \(\frac{4d-6}{7}\)
22 Jan 2018, 07:05
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Please see my approach 
Bunuel
If a, b, c, and d are consecutive integers and a < b < c < d, what is the average (arithmetic mean) of a, b, c, and d in terms of d?
(A) d – 5/2
(B) d – 2
(C) d – 3/2
(D) d + 3/2
(E) (4d – 6)/7
(A) d – 5/2
(B) d – 2
(C) d – 3/2
(D) d + 3/2
(E) (4d – 6)/7
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22 Jan 2018, 02:02
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Since they are consecutive integers, therefore a=d-3; b=d-2; c=d-1;
Taking average,
(d-3+d-2+d-1+d)/4 = (4d-6)/4 = d-3/2
Option C.
Sent from my ONE E1003 using GMAT Club Forum mobile app
Taking average,
(d-3+d-2+d-1+d)/4 = (4d-6)/4 = d-3/2
Option C.
Sent from my ONE E1003 using GMAT Club Forum mobile app
