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26% (01:30) correct
74%
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wrong
based on 106
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If a*b is an even integer, is b a multiple of 2?
(1) a is not a multiple of 2.
(2) b is product of two consecutive integers.
Self made
(1) a is not a multiple of 2.
(2) b is product of two consecutive integers.
Self made
19 Jul 2017, 21:33
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if a*b is an even integer and
1) a is not multiple of 2 then b must be multiple of 2 for a*b to be an even number Sufficient
2) b is product of two consecutive no. let take b=3*4 or b=11*12 so as you see b is even Sufficient
Answer is D
1) a is not multiple of 2 then b must be multiple of 2 for a*b to be an even number Sufficient
2) b is product of two consecutive no. let take b=3*4 or b=11*12 so as you see b is even Sufficient
Answer is D
19 Jul 2017, 22:36
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If a*b is an even integer, is b a multiple of 2?
1. a is not a multiple of 2.
If a is not a multiple of 2
Case 1: If a = 1, and b = 2. The expression a*b is an even integer and a is a multiple of 2
Case 2: If a = 2/3 and b = 3. The expression a*b is an even integer and a is not a multiple of 2(Insufficient)
2. b is product of two consecutive integers.
If b is a product of 2 consecutive integers, it has to be even*odd or odd*even
b will be a multiple of 2. (Sufficient) (Option B)
1. a is not a multiple of 2.
If a is not a multiple of 2
Case 1: If a = 1, and b = 2. The expression a*b is an even integer and a is a multiple of 2
Case 2: If a = 2/3 and b = 3. The expression a*b is an even integer and a is not a multiple of 2(Insufficient)
2. b is product of two consecutive integers.
If b is a product of 2 consecutive integers, it has to be even*odd or odd*even
b will be a multiple of 2. (Sufficient) (Option B)
