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megafan
Joined: 28 May 2009
Last visit: 15 Oct 2017
Posts: 137
Given Kudos: 91
Location: United States
Concentration: Strategy, General Management
Schools: Stern PT Fall'18 Booth PT '18
GMAT Date: 03-22-2013
GPA: 3.57
WE:Information Technology (Consulting)
31 Jan 2013, 17:45
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
79% (01:53) correct
21%
(02:36)
wrong
based on 335
sessions
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If a certain bus line's ridership in July was \(\frac{3}{5}\) of its ridership in June, and its ridership in August was \(\frac{1}{3}\) of its ridership in July, then the bus line's ridership in June was how many times the average (arithmetic mean) of its ridership in July and August?
(A) \(\frac{1}{2}\)
(B) \(1\frac{2}{3}\)
(C) \(2\)
(D) \(2\frac{1}{2}\)
(E) \(5\)
Relatively easy problem. For some reason I'm getting different answer when I tried using variables and when I tried using numbers. I think my variable approach is wrong, can someone explain using variable approach?
Source: Sackmann's 1800 set
(A) \(\frac{1}{2}\)
(B) \(1\frac{2}{3}\)
(C) \(2\)
(D) \(2\frac{1}{2}\)
(E) \(5\)
Relatively easy problem. For some reason I'm getting different answer when I tried using variables and when I tried using numbers. I think my variable approach is wrong, can someone explain using variable approach?
Source: Sackmann's 1800 set
31 Jan 2013, 20:40
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Bookmarks
megafan
Let the ridership in June be x. Then in july, the ridership would be 3x/5 and thereby in August be x/5. The mean of riderships in the month of July and August would be 2x/5 (no need to calculate, just pick the in between number).
Now the question asks : the ridership in June is how many times that of the average that we just found.
Therefore x/(2x/5)=5/2.
Hope that helps.
megafan
Joined: 28 May 2009
Last visit: 15 Oct 2017
Posts: 137
Given Kudos: 91
Location: United States
Concentration: Strategy, General Management
Schools: Stern PT Fall'18 Booth PT '18
GMAT Date: 03-22-2013
GPA: 3.57
WE:Information Technology (Consulting)
31 Jan 2013, 20:50
Kudos
Bookmarks
Thanks Marcab. I made a silly mistake when taking the average with the reciprocal and arrived at 8x/5, which of course should be 2x/5. Anyway, I tend to make these silly mistakes once in a while, especially when I am doing the Math in my head. I will practice to make good use of my scratch paper from now.
