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# If a circular region has radius r and area k, then k/r is equal to

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Math Expert
Joined: 02 Sep 2009
Posts: 46991
If a circular region has radius r and area k, then k/r is equal to [#permalink]

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16 Nov 2017, 01:48
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93% (00:18) correct 7% (01:03) wrong based on 42 sessions

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If a circular region has radius r and area k, then k/r is equal to

(A) π
(B) 2π
(C) π/r
(D) r/π
(E) rπ

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Intern
Joined: 08 Aug 2017
Posts: 11
Re: If a circular region has radius r and area k, then k/r is equal to [#permalink]

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16 Nov 2017, 04:28
k/r = pi *r*r/r
=pi*r
hence, E
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Re: If a circular region has radius r and area k, then k/r is equal to [#permalink]

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16 Nov 2017, 05:13
Bunuel wrote:
If a circular region has radius r and area k, then k/r is equal to

(A) π
(B) 2π
(C) π/r
(D) r/π
(E) rπ

Area = π$$r^2$$ = k
So, k/r = πr
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Re: If a circular region has radius r and area k, then k/r is equal to [#permalink]

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16 Nov 2017, 09:42
Bunuel wrote:
If a circular region has radius r and area k, then k/r is equal to

(A) π
(B) 2π
(C) π/r
(D) r/π
(E) rπ

Area k = $$πr^2$$

So, $$\frac{k}{r}$$ = $$πr$$

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Re: If a circular region has radius r and area k, then k/r is equal to [#permalink]

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17 Nov 2017, 14:32
Bunuel wrote:
If a circular region has radius r and area k, then k/r is equal to

(A) π
(B) 2π
(C) π/r
(D) r/π
(E) rπ

Since area = k = πr^2:

k/r = πr^2/r = πr

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Re: If a circular region has radius r and area k, then k/r is equal to   [#permalink] 17 Nov 2017, 14:32
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