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24 Dec 2025, 13:31
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shyind
16 Apr 2026, 11:25
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Bunuel, pls help! I have a doubt- shouldn't the favourable outcomes be 1x5x5= 25 and then 25 multiplied by 3! because the 3 numbers could be arranged in 3! ways..I don't understand why we just did only 3 because 3 can come in any of the 3 throws..
16 Apr 2026, 11:38
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Isha2701
You do not multiply by 3! because the two “not 3” rolls are already being counted separately in that 5 * 5, so their order is already built in. The only extra choice left is where the single 3 goes, and that gives 3 positions, not 6. So the correct count is 25 * 3 = 75, not 25 * 6.
31 May 2026, 20:07
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Hi, I have a doubt
What about cases where the result after rolling the die is 311, 232, 553 etc.? why have we not separated similar and dissimilar cases?
Shouldnt the similar cases be multiplied by 3!/2! and dissimilar cases be multiplied by 3!?
What about cases where the result after rolling the die is 311, 232, 553 etc.? why have we not separated similar and dissimilar cases?
Shouldnt the similar cases be multiplied by 3!/2! and dissimilar cases be multiplied by 3!?
KarishmaB
