Bunuel
If a is a positive even integer, and ab is a negative even integer, then b must be which of the following?
A. A negative number
B. A negative even integer
C. A negative integer
D. A positive even integer
E. A positive integer
Given a=positive even
ab=negative even
For ab to be negative even , there are 3 cases of b:-
When a=18
1. b=-2, so ab=18*(-2)=-36 (here b is negative even integer)--------option D & E eliminated.
2. b=-3, so ab=18*(-3)=-54 (here b is negative odd integer)--------option B eliminated.
3. b=\(\frac{-1}{3}\), so ab=18*\(\frac{-1}{3}\)=-6 (here b is rational number)----------------option C eliminated.
Therefore, Since a*b is negative even & a is positive even, so 'b' is always a negative number.
Caution:- This is a
MUST BE TRUE question.
Ans. (A)
In my opinion the answer should be C. The question asks b "must be" what ? With your example 18*(-1/3) will result in an integer but 18*(-1/4) won't be an integer.
A would have been the answer if the question would have asked "could be". But the stem asks "must be". Thus, b must be a negative integer.
I would go with C.