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If a racehorse runs an average(arithmetic mean) of m miles per race fo

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If a racehorse runs an average(arithmetic mean) of m miles per race for r races and then runs n miles in its next race, what is the average number of miles the horse has run for the r + 1 races?

a) (rm + n)/r+1
b) (m + n)/r+1
c) (m + n)/r
d) r(m + n)/r+1
e) (m + rn)/r+1

Please assist with above problem.
[Reveal] Spoiler: OA

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Average miles ran per race = m for r no of races. So total miles = m*r

Miles ran in next race = n

Total Miles ran = m*r + n in r+1 races

Average miles = Total miles/Total no of races = (m*r + n)/(r + 1)

Option A

HTH

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Re: If a racehorse runs an average(arithmetic mean) of m miles per race fo [#permalink]

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New post 19 Oct 2016, 08:24
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alanforde800Maximus wrote:
If a racehorse runs an average(arithmetic mean) of m miles per race for r races and then runs n miles in its next race, what is the average number of miles the horse has run for the r + 1 races?

a) (rm + n)/r+1
b) (m + n)/r+1
c) (m + n)/r
d) r(m + n)/r+1
e) (m + rn)/r+1

Please assist with above problem.


Total distance run in \(r\) races = \(rm\)
Distance run in last race is \(n\)

So, Total Distance Run = \(rm\) \(+\) \(n\)
Total run = \(r + 1\)

Hence average will be \(\frac{rm + n}{r+1}\)

So, Correct answer will be (A)

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Thanks and Regards

Abhishek....

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Re: If a racehorse runs an average(arithmetic mean) of m miles per race fo   [#permalink] 19 Oct 2016, 08:24
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