AbhishekGopal
Hi Bunuel,
Could you please tell me how you got B as the answer choice?
I got D as the answer.
Hi
AbhishekGopal,
Here is how D is incorrect:
ab > 9
ab/9 > 1
a(b/9) > 1
stmt-1: b < 9
if b < 9 then b/9 < 1
a*something-less-than-1 > 1 shows that a has to be greater than 1 i.e. a > 1. so you say this sentence is fine. is this sufficient?
stmt-2:
1 < b < 8
again it means b/9 < 1 and reasoning is same a*something-less-than-1 > 1 shows that a has to be greater than 1.
but wait we are getting the same answer from both the statements but are the ranges provided for b by both the statements SAME? No!
in stmt-1 b can be -ve also.
all right so if b is negative then a also has to be -ve for a(b/9) > 1 to be true. which means a < 1. so this proves that stmt-1 is not sufficient.
I wanted to prove two things here:
#1. If i followed the process of evaluating the statement very carefully then i would not have gotten into the trap initially in statement-1. but now that i was trapped:
#2. Take help from the other statement. Great, this told me that there was sometthing fishy about statement-1.
Trap - We generally forget to test the -ve values. Learning!