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01 Jan 2011, 12:48
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:17) correct
27%
(01:42)
wrong
based on 209
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If ab < ac, which is greater b or c ?
(1) a < 0
(2) c < 0
(1) a < 0
(2) c < 0
This question if from Kaplan Premier 2009. Practice quiz #5
As per the answer its is A. The explanation if a is -ve the we can derive that b>c..
But 'a' can be positive also , let assume that a=.5
in this case B<c
So we are nor pretty sure about the value of 'a'. So how the answer is A.
As per the answer its is A. The explanation if a is -ve the we can derive that b>c..
But 'a' can be positive also , let assume that a=.5
in this case B<c
So we are nor pretty sure about the value of 'a'. So how the answer is A.
01 Jan 2011, 13:02
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Riju1191
If ab<ac, which is greater b or c?
Given that \(ab<ac\) --> \(ac-ab>0\) --> \(a(c-b)>0\), so \(a\) and \(c-b\) are either both positive or both negative.
(1) a<0 --> as \(a\) is negative then \(c-b\) is negative too --> \(c-b<0\) --> \(c<b\). Sufficient.
(2) c<0. Clearly insufficient.
Answer: A.
As for your doubt: statement (1) says that \(a<0\), so \(a\) is negative and can not equal to 0.5 (or any other non-negative value).
Hope it's clear.
01 Jan 2011, 13:29
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If ab<ac , which is greater b or c ?
i. a<0
2. c<0
As you said
Both a or c-b should be +ve or both should be -ve.
Let assume
a= .1 its is a positive
b = .1
c= .2
AB = .1*.1 = 0.01
AC = .1*.2 = 0.02
so ab< ac
In this case
if a < 0 and a is -ve then b>c
but if a<0 and +ve then C>b
So we are not pretty sure.. Again in the question it is not mentioned that a,b,c are integer
i. a<0
2. c<0
As you said
Both a or c-b should be +ve or both should be -ve.
Let assume
a= .1 its is a positive
b = .1
c= .2
AB = .1*.1 = 0.01
AC = .1*.2 = 0.02
so ab< ac
In this case
if a < 0 and a is -ve then b>c
but if a<0 and +ve then C>b
So we are not pretty sure.. Again in the question it is not mentioned that a,b,c are integer
