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If AD = 3x, AE = 5x, EB = y and DC = 5y, what is the ratio of the area

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Math Expert
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If AD = 3x, AE = 5x, EB = y and DC = 5y, what is the ratio of the area  [#permalink]

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New post 21 Aug 2018, 06:03
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

91% (01:28) correct 9% (02:31) wrong based on 41 sessions

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Re: If AD = 3x, AE = 5x, EB = y and DC = 5y, what is the ratio of the area  [#permalink]

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New post 21 Aug 2018, 06:17
Area of triangle DEC = 1/2*AD*DC ( AD will be the height of the triangle)
DEC = 1/2*5Y*3X = 15XY/2

Now area of rectangle ABCD = AD*DC = 5Y*3X = 15XY

The ratio becomes 15XY/2 : 15XY
Which is equal to 1:2

D is the answer

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Re: If AD = 3x, AE = 5x, EB = y and DC = 5y, what is the ratio of the area  [#permalink]

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New post 21 Aug 2018, 23:05

Solution



Given:
    • In the given figure, AD = 3x, AE = 5x, EB = y and DC = 5y

To find:
    • The ratio of the area of triangle DEC to the area of rectangle ABCD

Approach and Working:
    • The area of the triangle DEC = ½ x DC x AD = ½ x 5y x 3x
    • The area of the rectangle ABCD = DC x AD= 5y x 3x
    • Hence, the ratio = (½ x 5y x 3x): (5y x 3x) = ½: 1 = 1: 2

Hence, the correct answer is option D.

Answer: D

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Re: If AD = 3x, AE = 5x, EB = y and DC = 5y, what is the ratio of the area   [#permalink] 21 Aug 2018, 23:05
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If AD = 3x, AE = 5x, EB = y and DC = 5y, what is the ratio of the area

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