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If Anne takes 3x seconds to run y yards, how many minutes will she tak

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If Anne takes 3x seconds to run y yards, how many minutes will she tak  [#permalink]

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New post Updated on: 19 Jan 2019, 11:22
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Difficulty:

  35% (medium)

Question Stats:

76% (01:31) correct 24% (01:53) wrong based on 112 sessions

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If Anne takes 3x seconds to run y yards, how many minutes will she take to run 10z yards?

A. \(\frac{xy}{2z}\)

B. \(\frac{xz}{2y}\)

C. \(\frac{10z}{3xy}\)

D. \(\frac{z}{18xy}\)

E. \(\frac{zy}{18x}\)

Source: Experts Global GMAT
Difficulty Level: 600

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Originally posted by SajjadAhmad on 15 Oct 2018, 10:55.
Last edited by SajjadAhmad on 19 Jan 2019, 11:22, edited 1 time in total.
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Re: If Anne takes 3x seconds to run y yards, how many minutes will she tak  [#permalink]

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New post 15 Oct 2018, 15:39
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First find the rate

Rate (speed) = distance/time = y/3x

Convert the 3x from seconds to minutes it will be 3x/60 = x/20

Rate = y/(x/20) = 20y/x (yards/mins)

To find the time for 10z yards

It will be time = distance/rate

10z/(20y/x) = 10xz/20y = xz/2y

Answer choice B

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Re: If Anne takes 3x seconds to run y yards, how many minutes will she tak  [#permalink]

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New post 15 Oct 2018, 19:08
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When i see such questions, I first see which conversion is the question looking at.

Now, lets solve this question

Question speaks about minutes, So i will convert the seconds part into minutes

3x seconds to complete y yards

60 seconds(1 minute) will now take \(\frac{y}{3x}\)* 60 yards

Now we know the work done in a minute, we can now calculate, how much time will 10 z yards take

\(\frac{y}{3x}\)* 60 will be done in 1 minute

10 z will be done in \(\frac{3x}{(y*60)}\)*10Z

Solving that will give answer as
\(\frac{xz}{2y}\)

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Re: If Anne takes 3x seconds to run y yards, how many minutes will she tak  [#permalink]

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New post 16 Oct 2018, 00:32
SajjadAhmad wrote:
If Anne takes 3x seconds to run y yards, how many minutes will she take to run 10z yards?

A. \(\frac{xy}{2z}\)

B. \(\frac{xz}{2y}\)

C. \(\frac{10z}{3xy}\)

D. \(\frac{z}{18xy}\)

E. \(\frac{zy}{18x}\)

EG


Speed (in yards/min) = Distance (in yards)/Time (in mins) \(= \frac{y}{3x/60} = \frac{20y}{x}\)

Time taken in mins = Distance (in yards)/Speed (in yards/min) \(= \frac{10z}{20y/x} = \frac{xz}{2y}\)

Answer (B)
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Re: If Anne takes 3x seconds to run y yards, how many minutes will she tak  [#permalink]

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New post 16 Oct 2018, 17:13
1
SajjadAhmad wrote:
If Anne takes 3x seconds to run y yards, how many minutes will she take to run 10z yards?

A. \(\frac{xy}{2z}\)

B. \(\frac{xz}{2y}\)

C. \(\frac{10z}{3xy}\)

D. \(\frac{z}{18xy}\)

E. \(\frac{zy}{18x}\)

EG


Since Anne’s rate is y/3x, it will take her 10z/(y/3x) = 30zx/y seconds or 30zx/60y = zx/2y minutes to run 10z yards.

Alternate Solution:

Let’s first convert 3x seconds to minutes: 3x/60 = x/20 minutes. Thus, it takes Anne x/20 minutes to run y yards.

Now we can set up a proportion, letting m = the number of minutes it will take her to run 10z yards. The proportion is: “x/20 minutes is to y yards as m minutes is to 10z yards”:

(x/20)/y = m/10z

Cross-multiplying, we have:

10xz/20 = my

Solving for m, we have:

10xz/20y = m

xz/2y = m

Answer: B
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Re: If Anne takes 3x seconds to run y yards, how many minutes will she tak  [#permalink]

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New post 18 Jan 2019, 17:32
Plugging in values:

3(x) ... take 60 as x.

So 180 sec = 3 minutes.

y yards ... take 6 as yards (because is a multiple of 3).

This means that Anne takes 2 minutes per yard (6yards(y)/3minutes(x))

Then, 10z ... take z as 3, so total will be 30 ... (because is a multiple of 6)

Solve it: 30/2 = 15 minutes.

So just look for the answer which gives you 15 (answers are given in minutes).

X = 60
Y = 6
Z = 3


B) (60)(3)/2(6) =15 minutes.

B
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Re: If Anne takes 3x seconds to run y yards, how many minutes will she tak   [#permalink] 18 Jan 2019, 17:32
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If Anne takes 3x seconds to run y yards, how many minutes will she tak

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