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Re: If b and c are two-digit positive integers and b − c = 22d, is d [#permalink]
I have a confusion here
from 2 we get
b+c= 22x
and from original question b-c =22d
adding both together
2b= 22(d+x)
b=11(d+x)
x is integer , b is integer
then d has to be integer
so answer of mine comes B
Experts please help
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Re: If b and c are two-digit positive integers and b − c = 22d, is d [#permalink]
Expert Reply
Rahilforever wrote:
I have a confusion here
from 2 we get
b+c= 22x
and from original question b-c =22d
adding both together
2b= 22(d+x)
b=11(d+x)
x is integer , b is integer
then d has to be integer
so answer of mine comes B
Experts please help


d could be a fraction with denominator 11.

For example d=\(\frac{1}{11}\), b=14 and x=3.

b=\(14=11(\frac{1}{11}+3)\)
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Re: If b and c are two-digit positive integers and b c = 22d, is d [#permalink]
What if b = 122 and c = 10, these values satisfy statement 1 and 2, but b-c(=112) is not divisible by 22.
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Re: If b and c are two-digit positive integers and b c = 22d, is d [#permalink]
Rafiuddin wrote:
What if b = 122 and c = 10, these values satisfy statement 1 and 2, but b-c(=112) is not divisible by 22.


Not allowed.
The question clearly says b and c are 2-digit integers, and the value you have picked for b is not a 2-digit integer.
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Re: If b and c are two-digit positive integers and b c = 22d, is d [#permalink]
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