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If d = 2.0453 and d* is the decimal obtained by rounding d
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28 Jan 2014, 02:06
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The Official Guide For GMAT® Quantitative Review, 2ND EditionIf d = 2.0453 and d* is the decimal obtained by rounding d to the nearest hundredth, what is the value of d*  d ? (A) 0.0053 (B) 0.0003 (C) 0.0007 (D) 0.0047 (E) 0.0153 Problem Solving Question: 65 Category: Arithmetic Operations on rational numbers Page: 70 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you!
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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28 Jan 2014, 02:06
SOLUTIONIf d = 2.0453 and d* is the decimal obtained by rounding d to the nearest hundredth, what is the value of d*  d ?(A) 0.0053 (B) 0.0003 (C) 0.0007 (D) 0.0047 (E) 0.0153 2.0453 rounding the nearest hundredth is 2.05, thus d*  d = 2.05  2.0453 = 0.0047. Answer: D. Rounding rulesRounding is simplifying a number to a certain place value. To round the decimal drop the extra decimal places, and if the first dropped digit is 5 or greater, round up the last digit that you keep. If the first dropped digit is 4 or smaller, round down (keep the same) the last digit that you keep.Example: 5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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28 Jan 2014, 03:36
d=2.0453 rounded to the nearest hundredth is 2.0450=d*. So d*d=0.0003. Answer B



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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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28 Jan 2014, 10:26
Bunuel wrote: If d = 2.0453 and d* is the decimal obtained by rounding d to the nearest hundredth, what is the value of d*  d ?
(A) 0.0053 (B) 0.0003 (C) 0.0007 (D) 0.0047 (E) 0.0153
] Sol: given d=2.0453 so when rounded to nearest hundredth will be 2.05 so d*  d = 2.05.  2.0453 = 0.0047 Ans D
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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28 Jan 2014, 13:06
+1 for D
2.0453 rounded to nearest hundredth is 2.05



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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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28 Jan 2014, 23:30
d = 2.0453; Here, the hundredth digit is 4 and thousandth's digit is 5; Therefore, rounding off to the hundredth digit to a higher number will give 2.05; So, d* = 2.05;
d*  d = 2.05  2.0453 = 0.0047;
Ans is (D).



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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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29 Jan 2014, 03:17
Rounded to nearest 100 d=2.0500 Hence d*d=2.05002.0453=.0047 Ans D



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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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01 Feb 2014, 08:30
SOLUTIONIf d = 2.0453 and d* is the decimal obtained by rounding d to the nearest hundredth, what is the value of d*  d ?(A) 0.0053 (B) 0.0003 (C) 0.0007 (D) 0.0047 (E) 0.0153 2.0453 rounding the nearest hundredth is 2.05, thus d*  d = 2.05  2.0453 = 0.0047. Answer: D. Rounding rulesRounding is simplifying a number to a certain place value. To round the decimal drop the extra decimal places, and if the first dropped digit is 5 or greater, round up the last digit that you keep. If the first dropped digit is 4 or smaller, round down (keep the same) the last digit that you keep.Example: 5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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02 Feb 2014, 07:45
If d = 2.0453 and d* is the decimal obtained by rounding d to the nearest hundredth, what is the value of d*  d ?
(A) 0.0053 (B) 0.0003 (C) 0.0007 (D) 0.0047 (E) 0.0153
d = 2.0453
Rounding d to the nearest hundredth, d* = 2.05
So, d*  d = 2.05  2.0453 = 0.0047
Answer: (D)



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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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11 May 2014, 15:21
Hi Buenel
Quick one
You quoted : 5.3485 rounded to the nearest tenth is 5.3, since the dropped 4 is less than 5.
But shouldnt it be 5.4 , as 5.3485 rounded to nearest thousand = 5.349, rounded to nearest hundred = 5.35 and hence rounded to nearest ten = 5.4?



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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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12 May 2014, 00:07
gaurav1418z wrote: Hi Buenel
Quick one
You quoted : 5.3485 rounded to the nearest tenth is 5.3, since the dropped 4 is less than 5.
But shouldnt it be 5.4 , as 5.3485 rounded to nearest thousand = 5.349, rounded to nearest hundred = 5.35 and hence rounded to nearest ten = 5.4? No, it should be as written. When rounding to the nearest tenth the FIRST dropped digit is 4, less than 5, thus 5.3485 rounded to the nearest tenth = 5.3.
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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12 May 2014, 02:49
Sorry a little confused Bunuel
You stated in your posts
5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
I get the logic of the second and the third statement. As per second statement , 5.3485 rounded to hundredth= 5.35, and hence if we go ahead and further round 5.35 to the nearest tenth , shouldnt we get 5.4
If it was 5.34, it should yield 5.3, but for 5.3x, where x= 5,6,7,8,9 , shouldnt it round off to 5.4?



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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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12 May 2014, 02:56
gaurav1418z wrote: Sorry a little confused Bunuel
You stated in your posts
5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
I get the logic of the second and the third statement. As per second statement , 5.3485 rounded to hundredth= 5.35, and hence if we go ahead and further round 5.35 to the nearest tenth , shouldnt we get 5.4
If it was 5.34, it should yield 5.3, but for 5.3x, where x= 5,6,7,8,9 , shouldnt it round off to 5.4? Rounding is not cumulative, that is we are NOT rounding first to the hundredth and only then to the tenth. We are rounding directly to the tenth digit based on the hundredth digit. Thus, the only thing we are interested in when rounding to the nearest tenth is the hundredth digit, the only thing we are interested when rounding to the nearest hundredth is the thousandth digit, and so on.
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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12 May 2014, 03:01
Many Thanks Bunuel, i get it now.



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Re: If d = 2.0453 and d* is the decimal obtained by rounding d
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28 Aug 2016, 18:32
Here D* = 2.05 as the next digit immediately after the hundredths is 5. Hence D*D=0.0047 => Smash that D
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If d = 2.0453 and d* is the decimal obtained by rounding d
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28 Sep 2016, 02:57
sorry Bunuel, it is not completely clear to me. I've a question: if n was 2.0450 how would you approximate it to the nearest hundredth? 2.05 and 2.04 have the same distance from n (0.005)
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