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2.0453 rounding the nearest hundredth is 2.05, thus d* - d = 2.05 - 2.0453 = 0.0047.

Answer: D.

Rounding rules

Rounding is simplifying a number to a certain place value. To round the decimal drop the extra decimal places, and if the first dropped digit is 5 or greater, round up the last digit that you keep. If the first dropped digit is 4 or smaller, round down (keep the same) the last digit that you keep.

Example: 5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d [#permalink]

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28 Jan 2014, 23:30

1

This post received KUDOS

d = 2.0453; Here, the hundredth digit is 4 and thousandth's digit is 5; Therefore, rounding off to the hundredth digit to a higher number will give 2.05; So, d* = 2.05;

2.0453 rounding the nearest hundredth is 2.05, thus d* - d = 2.05 - 2.0453 = 0.0047.

Answer: D.

Rounding rules

Rounding is simplifying a number to a certain place value. To round the decimal drop the extra decimal places, and if the first dropped digit is 5 or greater, round up the last digit that you keep. If the first dropped digit is 4 or smaller, round down (keep the same) the last digit that you keep.

Example: 5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d [#permalink]

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12 May 2014, 02:49

Sorry a little confused Bunuel

You stated in your posts-

5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.

I get the logic of the second and the third statement. As per second statement , 5.3485 rounded to hundredth= 5.35, and hence if we go ahead and further round 5.35 to the nearest tenth , shouldnt we get 5.4

If it was 5.34, it should yield 5.3, but for 5.3x, where x= 5,6,7,8,9 , shouldnt it round off to 5.4?

5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.

I get the logic of the second and the third statement. As per second statement , 5.3485 rounded to hundredth= 5.35, and hence if we go ahead and further round 5.35 to the nearest tenth , shouldnt we get 5.4

If it was 5.34, it should yield 5.3, but for 5.3x, where x= 5,6,7,8,9 , shouldnt it round off to 5.4?

Rounding is not cumulative, that is we are NOT rounding first to the hundredth and only then to the tenth. We are rounding directly to the tenth digit based on the hundredth digit. Thus, the only thing we are interested in when rounding to the nearest tenth is the hundredth digit, the only thing we are interested when rounding to the nearest hundredth is the thousandth digit, and so on.
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Re: If d = 2.0453 and d* is the decimal obtained by rounding d [#permalink]

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18 Oct 2017, 02:05

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