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If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 11 days. If he works at reduced efficiency, he can work without break and finish that same job in 11 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?

Re: If Dale works at full efficiency he needs a break of 1 day after every [#permalink]

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21 Apr 2015, 05:26

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Hi, IMO it should be D 8/11. though I am not very confident for this but still a feeble attempt. Total working days were 8 days at original efficiency. new efficiency were 11 days so may be not a good approach even though answer might be of might not be correct. 8/11

Regards Celestial

Kudos for a correct answer or even for trying as if it would have been in exam then there wasn't any way to escape it.

Bunuel wrote:

If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 11 days. If he works at reduced efficiency, he can work without break and finish that same job in 11 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?

Re: If Dale works at full efficiency he needs a break of 1 day after every [#permalink]

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21 Apr 2015, 09:38

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IMO answer should be D- 11 days..

At full efficiency, he can finish the work in 8 days and at reduced efficiency he will complete the work in 11 days.

Hence 8/11

Bunuel wrote:

If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 11 days. If he works at reduced efficiency, he can work without break and finish that same job in 11 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?

Re: If Dale works at full efficiency he needs a break of 1 day after every [#permalink]

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22 Apr 2015, 00:09

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One more for D At full efficiency Dale works for 2+2+2+2 = 8 days, and 3 days rest. At reduced efficiency Dale works for full 11 days. Thus fraction = 8/11
_________________

If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 11 days. If he works at reduced efficiency, he can work without break and finish that same job in 11 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?

If Dale needs to rest every third day at full efficiency, that means he'll rest on days 3, 6, and 9 before finishing the job on day 11. That means that he'll have worked a total of 8 days, accomplishing 1/8 of the job each day.

At reduced efficiency, he works a total of 11 days, completing 1/11 of the job each day.

Therefore, the ratio of his output at reduced to his output at full is 1/11 : 1/8. That reduces to 8/11.
_________________

If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 11 days. If he works at reduced efficiency, he can work without break and finish that same job in 11 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?

A. 5/11 B. 6/11 C. 7/11 D. 8/11 E. 9/11

When Dale works at full efficiency, he actually works 8 days of the 11 days (notice that 2 + 1 + 2 + 1 + 2 + 1 + 2 = 11). When Dale works at reduced efficiency, he works 11 days.

If we let his output at reduced efficiency = r and his output at full efficiency = f, then we have:

11r = 8f

r/f = 8/11

Answer: D
_________________

Scott Woodbury-Stewart Founder and CEO

GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions

If Dale works at full efficiency he needs a break of 1 day after every [#permalink]

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05 Dec 2017, 13:39

Bunuel wrote:

If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 11 days. If he works at reduced efficiency, he can work without break and finish that same job in 11 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?

A. 5/11 B. 6/11 C. 7/11 D. 8/11 E. 9/11

Kudos for a correct solution.

I learned efficiency a bit differently, so this method was easier.

Full efficiency, X = one day's work: X X _ X X _ X X _ X X = \(\frac{1Job}{8days}\)