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Re: If f(a) = a^3 a^2, then f(1/3) = [#permalink]
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Top Contributor
Given that \(f(a) = a^{–3} – a^{–2}\) and we need to find the value of \(f(\frac{1}{3})\)

To find \(f(\frac{1}{3})\) we need to compare what is inside the ( ) in \(f(\frac{1}{3})\) and f(a)

=> We need to substitute a with \(\frac{1}{3}\) in \(f(a) = a^{–3} – a^{–2}\) to get the value of \(f(\frac{1}{3})\)

=> \(f(\frac{1}{3}) = (\frac{1}{3})^{–3} – (\frac{1}{3})^{–2}\) = \(3^3\) - \(3^2\) = 27 - 9 = 18

So, Answer will be E
Hope it helps!

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Re: If f(a) = a^3 a^2, then f(1/3) = [#permalink]
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Math Expert
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