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# If f(a) = a^–3 – a^–2, then f(1/3) =

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Re: If f(a) = a^3 a^2, then f(1/3) = [#permalink]
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Given that $$f(a) = a^{–3} – a^{–2}$$ and we need to find the value of $$f(\frac{1}{3})$$

To find $$f(\frac{1}{3})$$ we need to compare what is inside the ( ) in $$f(\frac{1}{3})$$ and f(a)

=> We need to substitute a with $$\frac{1}{3}$$ in $$f(a) = a^{–3} – a^{–2}$$ to get the value of $$f(\frac{1}{3})$$

=> $$f(\frac{1}{3}) = (\frac{1}{3})^{–3} – (\frac{1}{3})^{–2}$$ = $$3^3$$ - $$3^2$$ = 27 - 9 = 18

So, Answer will be E
Hope it helps!

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Re: If f(a) = a^3 a^2, then f(1/3) = [#permalink]
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