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If f(x) = x^2 + 11x + n and g(x) = x, then what is the value of the largest positive integer n for which f(x) = g(x) has two distinct real roots?

A. 22
B. 23
C. 24--> correct: f(x) = g(x) => x^2 + 11x + n =x => x^2 + 10x + n =0 =>(x-5)^2 = 5^2-n, because x has two distinct real roots, (x-5)^2 = 5^2-n > 0 => n<5^2 => n<25, so largest positive integer n = 24
D. 25
E. 26
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See the attachment. C
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1.PNG
1.PNG [ 20.97 KiB | Viewed 4903 times ]

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Bunuel
If f(x) = x^2 + 11x + n and g(x) = x, then what is the value of the largest positive integer n for which f(x) = g(x) has two distinct real roots?

A. 22
B. 23
C. 24
D. 25
E. 26


Solution:

Setting f(x) = g(x), we have:

x^2 + 11x + n = x

x^2 + 10x + n = 0

In order to have two distinct real roots, the discriminant b^2 - 4ac must be greater than 0. Therefore, we can create the inequality:

10^2 - 4(1)(n) > 0

100 - 4n > 0

100 > 4n

25 > n

Therefore, the largest positive integer value for n is 24.

Answer: C
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Not sure how correct is my approach, but it didn't take more than 15 seconds.

n's largest value and 2 distinct integers.

Started to plug answer in the original equation. Only factors of 24 (8 and 3) makes the sum = 11. Hence, answer is C.
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