i was looking for a nice tidy way to solve this kind of problems. i found one that fits me, might as well share it.
i like to put the rate, the number of people/cars, the number of hours ecc... on the left of the equation and only the percentage of job on the right.
in this example:
#machines = 5
#hours = 1/2 hours
%of job = 3/4
rate = 1/t
as the problem states this leads to the completion of 3/4 of the job, thus:
#machines * #hours * rate = 5 * 1/2 * rate = %of job completed = 3/4
5 * 1/2 * rate = 3/4
since i like the rate to be explicitly "something" over time --> i express it as 1/t
5*1/2 * 1/t = 3/4
1/t = 3/10
now we have to calculate the amount of time it takes to make 3/5 of the job in the following condition:
#machines = 2
#hours = x hours
%of job = 3/5
rate = 3/10
#machines * #hours * rate = 2 * x * 3/10 = %of job completed = 3/5
2 * x * 3/10 = 3/5
x = 3/5 * 10/3 * 1/2 = 1 HOUR --> 60 minutes