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28 Feb 2025, 01:30
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Difficulty:
75%
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Question Stats:
61% (02:57) correct
39%
(03:29)
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If, in a baseball game, a single picher can decide to throw either a 100mph fastball or 60mph knuckle ball on any pitch, how much less time, in seconds, does the batter have from when the ball is released as a fastball than when the ball is released as a knuckle ball? (Assume where the batter's point of contact is exactly 60ft away from the pitcher's release point. 5280ft = 1 mile.)
A. \(\frac{6}{22}s\)
B. \(\frac{7}{22}s\)
C. \(\frac{8}{22}s\)
D. \(\frac{9}{22}s\)
E. \(\frac{15}{22}s\)
A. \(\frac{6}{22}s\)
B. \(\frac{7}{22}s\)
C. \(\frac{8}{22}s\)
D. \(\frac{9}{22}s\)
E. \(\frac{15}{22}s\)
28 Feb 2025, 01:41
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D = 60/5280 = 1/88 mile
Time diff = D(1/S2 - 1/S1)
= 1/88 * (1/60 - 1/100)
= 1/88 * 40/60*100 hr
Time in sec
= 3600* 1/88 * 40/60*100
= 6/22 s
Time diff = D(1/S2 - 1/S1)
= 1/88 * (1/60 - 1/100)
= 1/88 * 40/60*100 hr
Time in sec
= 3600* 1/88 * 40/60*100
= 6/22 s
Bunuel
28 Feb 2025, 03:56
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| Knuckle | 60/3600 = 1/60 | 15/22 | 1/88 |
| Fastball | 100/3600 =1/36 | 9/22 | 1/88 |
| Diff. | 6/22 |
By applying the matrix approach we can reach an answer as 6/22.
Bunuel
