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16 Jun 2022, 14:45
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Difficulty:
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Question Stats:
72% (01:50) correct
28%
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wrong
based on 29
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If, in the diagram below, AB is 20 centimeters long, how many centimeters long is BC ?
(A) 5 cm
(B) 10 cm
(C) \(\frac{5 \sqrt{3}}{3}\) cm
(D) \(\frac{10\sqrt{3}}{3}\) cm
(E) \(\frac{20 \sqrt{3}}{3}\) cm
2021-01-14_16-33-59.png [ 19.42 KiB | Viewed 1275 times ]
(A) 5 cm
(B) 10 cm
(C) \(\frac{5 \sqrt{3}}{3}\) cm
(D) \(\frac{10\sqrt{3}}{3}\) cm
(E) \(\frac{20 \sqrt{3}}{3}\) cm
Attachment:
2021-01-14_16-33-59.png [ 19.42 KiB | Viewed 1275 times ]
16 Jun 2022, 16:01
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Surprised its showing in the 700 level section but anyways,
Here we have two 30-60-90 right triangles which have sides in the corresponding ratio (sides opposite to 30, 60 and 90 degree angles) of 1:√(3):2. So based on this we have been given that the hypothenuse of triangle ADB is 20 so based on above property:
BD = 10
AD = 10√3
Now in triangle DBC, DB is 10 so BC = 10/√3 and multiplying by √3 in both numerator and denominator, we get 10√3/3
D
Posted from my mobile device
Here we have two 30-60-90 right triangles which have sides in the corresponding ratio (sides opposite to 30, 60 and 90 degree angles) of 1:√(3):2. So based on this we have been given that the hypothenuse of triangle ADB is 20 so based on above property:
BD = 10
AD = 10√3
Now in triangle DBC, DB is 10 so BC = 10/√3 and multiplying by √3 in both numerator and denominator, we get 10√3/3
D
Posted from my mobile device
16 Jun 2022, 19:09
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Avish11
Surprised its showing in the 700 level section but anyways,
Here we have two 30-60-90 right triangles which have sides in the corresponding ratio (sides opposite to 30, 60 and 90 degree angles) of 1:√(3):2. So based on this we have been given that the hypothenuse of triangle ADB is 20 so based on above property:
BD = 10
AD = 10√3
Now in triangle DBC, DB is 10 so BC = 10/√3 and multiplying by √3 in both numerator and denominator, we get 10√3/3
D
Posted from my mobile device
Here we have two 30-60-90 right triangles which have sides in the corresponding ratio (sides opposite to 30, 60 and 90 degree angles) of 1:√(3):2. So based on this we have been given that the hypothenuse of triangle ADB is 20 so based on above property:
BD = 10
AD = 10√3
Now in triangle DBC, DB is 10 so BC = 10/√3 and multiplying by √3 in both numerator and denominator, we get 10√3/3
D
Posted from my mobile device
its not AD 10/Rooot 3
its BC i thik ques s flawed
Answere must be 10/Root 3
but no option has such value so check the ques posting
