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Bunuel
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magesh.d
J - K is even

Then J and K both should be both even or odd
If both J & K are even then J*k is even
If both J & K are odd then J*k is odd

Question asks only possible choice, so
answer is B


The question doesn't ask about possible choice, but "MUST" choice
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Bunuel
If j and k are integers and j — k is even, which of the following must be even?

A) k

B) jk

C) j + 2k

D) jk + j

E) jk — 2j


This question is about must be true option. It means we have to assess all the probable aspects.

We know ,

Even - Even = Even
Odd - Odd = Even

Then start implementing plugging in method.

Only option D meets out expectations.

The best answer is D.
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