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30 Sep 2012, 22:26
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Question Stats:

100% (01:53) correct 0% (00:00) wrong based on 7 sessions

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If Jack bought a computer for $1000 more than a generic model, then the price of that computer would have been 8 times the value of the accompanying bonus wireless router, which is 1/4th the price of the generic model. What is the price of the computer? I've translated the words into the equations but can't approach it. Please help.. Here's what I did: c =$1000 + g
c = 8b
b = (1/4) g

Thanks!
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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink] ### Show Tags 30 Sep 2012, 22:45 rainbooow wrote: If Jack bought a computer for$1000 more than a generic model, then the price of that computer would have been 8 times the value of the accompanying bonus wireless router, which is 1/4th the price of the generic model. What is the price of the computer?

Here's what I did:
c = $1000 + g c = 8b b = (1/4) g Thanks! Continuing your approach and replace b with 1/4g in c= 8b We get c = 2g We also have c = 1000 + g Equating, we get 2g = 1000 + g => g = 1000 Hence, the price of the computer = 2g =$2000
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01 Oct 2012, 04:55
c = $1000 + g is correct C = g + 1000 seems the same but the correct translation is the second one _________________ Intern Joined: 10 Jun 2012 Posts: 14 Followers: 0 Kudos [?]: 41 [0], given: 66 Re: If Jack bought a computer for$1000 more than a generic mode [#permalink]

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01 Oct 2012, 05:17
carcass wrote:
c = $1000 + g is correct C = g + 1000 seems the same but the correct translation is the second one I like them both Re: If Jack bought a computer for$1000 more than a generic mode   [#permalink] 01 Oct 2012, 05:17
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