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Updated on: 21 Mar 2020, 01:16
Originally posted by Deepaakrishnan on 20 Mar 2020, 22:19.
Last edited by Bunuel on 21 Mar 2020, 01:16, edited 1 time in total.
Last edited by Bunuel on 21 Mar 2020, 01:16, edited 1 time in total.
Renamed the topic and edited the question.
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C
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Difficulty:
35%
(medium)
Question Stats:
67% (01:37) correct
33%
(01:49)
wrong
based on 83
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If k is an even integer, what is the remainder when k is divided by 10?
1) the remainder when k is divided by 5 is equal to the remainder when k ia divided by 10
2) the remainder is greater than 3
1) the remainder when k is divided by 5 is equal to the remainder when k ia divided by 10
2) the remainder is greater than 3
The answer to this question was c
Tht is remainder =4
My doubt:
When even int k is divided by 5 we get a cycle of remainders 0,2,4,1 and 3
But when k(say k =16) is divided by 10 we get remainder as 6
How then can the remainder be equal to 4? Shouldnt the answer be e?
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Tht is remainder =4
My doubt:
When even int k is divided by 5 we get a cycle of remainders 0,2,4,1 and 3
But when k(say k =16) is divided by 10 we get remainder as 6
How then can the remainder be equal to 4? Shouldnt the answer be e?
Posted from my mobile device
ArunSharma12
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20 Mar 2020, 23:24
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Deepaakrishnan
The approach to solve this problem is as follows:
Given: K is even integer.
statement 1:
remainder when k is divided by 5 = [0,2,4]
remainder when k is divided by 10 = [0,2,4,6,8]
possible remainders = [0,2,4]; not sufficient
statement 2:
remainder is greater than 3 = [4,6,8];not sufficient
combining both statements,
possible remainder = [4].
Quote:
remainder with 10: 6
remainder with 5: 1
this number gets filtered out in statement 1.
20 Mar 2020, 23:47
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Thank you...very clear explanation
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Posted from my mobile device
