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If L ≠ 0, is 18K/L an integer?

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Manager
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If L ≠ 0, is 18K/L an integer?  [#permalink]

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New post 09 May 2010, 02:28
4
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A
B
C
D
E

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46% (01:36) correct 54% (01:18) wrong based on 67 sessions

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If L ≠ 0, is 18K/L an integer?


(1) K^2/L^2 is an integer.

(2) K - L = L
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Re: If L ≠ 0, is 18K/L an integer?  [#permalink]

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New post 09 May 2010, 03:10
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Re: If L ≠ 0, is 18K/L an integer?  [#permalink]

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New post 16 May 2010, 11:32
according to statement A K^2/L^2 is integer but that doesn't mean that K & L are integer; square of 1.732 is 3 which is an integer but 1.732 itself is not a integer. hence statement A - i nsufficient

statment B - k=2l sufficeint we get a integer from it
so B must be the answer.
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Re: If L ≠ 0, is 18K/L an integer?  [#permalink]

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New post 07 Jul 2020, 11:24
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Re: If L ≠ 0, is 18K/L an integer?   [#permalink] 07 Jul 2020, 11:24

If L ≠ 0, is 18K/L an integer?

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