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If Line k in the xyplane has equation y = mx + b, where m
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02 Sep 2010, 12:52
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If Line k in the xyplane has equation y = mx + b, where m and b are constants, what is the slope of k? (1) k is parallel to the line with equation y = (1m)x + b +1. (2) k intersects the line with equation y = 2x + 3 at the point (2, 7).
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If Line k in the xyplane has equation y = mx + b, where m
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26 Mar 2012, 14:15
For Coordinate Geometry check: 24. Coordinate Geometry For more check: ALL YOU NEED FOR QUANT ! ! !Ultimate GMAT Quantitative MegathreadHope it helps.
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If Line k in the xyplane has equation y = mx + b, where m
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26 Mar 2012, 13:56
If Line k in the xyplane has equation y = mx + b, where m and b are constants, what is the slope of k?
(1) k is parallel to the line with equation y = (1m)x + b +1. (2) k intersects the line with equation y = 2x + 3 at the point (2, 7)
I have a doubt in stmnt (2). K intersects the line with equation y=2(x)+3 at point (2,7) means for the line y=2(x)+3 slope is 2,but with this we cannot able to find slope of the line K. is my reasoning is right. please explain




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If Line k in the xyplane has equation y = mx + b, where m
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02 Sep 2010, 13:19
If Line k in the xyplane has equation y = mx + b, where m and b are constants, what is the slope of k?\(y=mx+b\) is called pointintercept form of equation of a line. Where: \(m\) is the slope of the line; \(b\) is the yintercept of the line; \(x\) is the independent variable of the function \(y\). So we are asked to find the value of \(m\). (1) k is parallel to the line with equation y = (1m)x + b +1 > parallel lines have the same slope > slope of this line is \(1m\), so \(1m=m\) > \(m=\frac{1}{2}\). Sufficient. (2) k intersects the line with equation y = 2x + 3 at the point (2, 7) > so line k contains the point (2,7) > \(7=2m+b\) > can not solve for \(m\). Not sufficient. Answer: A.
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Re: coordinate geometry
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26 Mar 2012, 14:14
Quote: If Line k in the xyplane has equation y = mx + b, where m and b are constants, what is the slope of k? (1) k is parallel to the line with equation y = (1m)x + b +1. (2) k intersects the line with equation y = 2x + 3 at the point (2, 7)
I have a doubt in stmnt (2). K intersects the line with equation y=2(x)+3 at point (2,7) means for the line y=2(x)+3 slope is 2,but with this we cannot able to find slope of the line K. is my reasoning is right. please explain My 2 cents: Questions is asking you what is the value of M so 1) Since k and this line with slope (1m) are parallel then m = 1  m or m = 1/2 thus it is sufficient 2) we know that the point 2, 7 is on the line line y = mx + b so 7 = 2m + b But we know nothing else so we cannot solve for m thus it is insufficient



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Re: Coordinate Geometry 2
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07 Jun 2012, 00:54
For line K, y=mx+b implies slope=m
From Statement1,
As slopes of parallel lines are equal, m = (1m)
m=1/2 Statement1 is sufficient.
From statement2,
line K passes through (2,7) 7=2.m + b m = (7b)/2 Not sufficient.
Ans:A



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If Line k in the xyplane has equation y = mx + b, where m
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29 Mar 2019, 13:51
Hi chetan2u, VeritasKarishma, Bunuel, amanvermagmat, gmatbusters, I did not understood the bold part in below question, can any please assist. Bunuel wrote: If Line k in the xyplane has equation y = mx + b, where m and b are constants, what is the slope of k?
\(y=mx+b\) is called pointintercept form of equation of a line. Where: \(m\) is the slope of the line; \(b\) is the yintercept of the line; \(x\) is the independent variable of the function \(y\).
So we are asked to find the value of \(m\).
(1) k is parallel to the line with equation y = (1m)x + b +1 > parallel lines have the same slope > slope of this line is \(1m\), so \(1m=m\) > \(m=\frac{1}{2}\). Sufficient.
(2) k intersects the line with equation y = 2x + 3 at the point (2, 7) > so line k contains the point (2,7) > \(7=2m+b\) > can not solve for \(m\). Not sufficient.
Answer: A.
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Re: If Line k in the xyplane has equation y = mx + b, where m
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29 Mar 2019, 23:05
Hi I couldd not get your query, the principle is as below: Attachment:
1.jpg [ 20.17 KiB  Viewed 2510 times ]
Attachment:
2.PNG [ 18.18 KiB  Viewed 2516 times ]
Gmatprep550 wrote: Hi chetan2u, VeritasKarishma, Bunuel, amanvermagmat, gmatbusters, I did not understood the bold part in below question, can any please assist. Bunuel wrote: If Line k in the xyplane has equation y = mx + b, where m and b are constants, what is the slope of k?
\(y=mx+b\) is called pointintercept form of equation of a line. Where: \(m\) is the slope of the line; \(b\) is the yintercept of the line; \(x\) is the independent variable of the function \(y\).
So we are asked to find the value of \(m\).
(1) k is parallel to the line with equation y = (1m)x + b +1 > parallel lines have the same slope > slope of this line is \(1m\), so \(1m=m\) > \(m=\frac{1}{2}\). Sufficient.
(2) k intersects the line with equation y = 2x + 3 at the point (2, 7) > so line k contains the point (2,7) > \(7=2m+b\) > can not solve for \(m\). Not sufficient.
Answer: A.
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Re: If Line k in the xyplane has equation y = mx + b, where m
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30 Mar 2019, 00:19
gmatbusters wrote: Hi I couldd not get your query, the principle is as below: Gmatprep550 wrote: Hi chetan2u, VeritasKarishma, Bunuel, amanvermagmat, gmatbusters, I did not understood the bold part in below question, can any please assist. Bunuel wrote: If Line k in the xyplane has equation y = mx + b, where m and b are constants, what is the slope of k?
\(y=mx+b\) is called pointintercept form of equation of a line. Where: \(m\) is the slope of the line; \(b\) is the yintercept of the line; \(x\) is the independent variable of the function \(y\).
So we are asked to find the value of \(m\).
(1) k is parallel to the line with equation y = (1m)x + b +1 > parallel lines have the same slope > slope of this line is \(1m\), so \(1m=m\) > \(m=\frac{1}{2}\). Sufficient.
(2) k intersects the line with equation y = 2x + 3 at the point (2, 7) > so line k contains the point (2,7) > \(7=2m+b\) > can not solve for \(m\). Not sufficient.
Answer: A. Hi gmatbustersApologies for not highlighting proper issue, I was not able to get following part. slope of this line is 1−m1−m, so 1−m=m1−m=m Even if slope is m then also how 1m = m? I feel that "m" mentioned in equation is different.
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______________________________ Press +1 Kudos if my post helped you a little and help me to ulcock the tests Wish you all success I'd appreciate learning about the grammatical errors in my posts
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Re: If Line k in the xyplane has equation y = mx + b, where m
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29 Jul 2019, 22:11
Parallel lines have same slopes buddy
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Re: If Line k in the xyplane has equation y = mx + b, where m
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29 Jul 2019, 22:11






