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# If m > 0 > n and m is odd, then all of the following could be odd and

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Math Expert
Joined: 02 Sep 2009
Posts: 59561
If m > 0 > n and m is odd, then all of the following could be odd and  [#permalink]

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19 Feb 2019, 01:03
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Difficulty:

55% (hard)

Question Stats:

58% (01:55) correct 42% (01:44) wrong based on 53 sessions

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If m > 0 > n and m is odd, then all of the following could be odd and positive EXCEPT

A. (mn)^2

B. n^3 – m^3

C. (m – n)^2

D. m^2 + n^2

E. m(m + n)
Intern
Joined: 18 Nov 2018
Posts: 27
Re: If m > 0 > n and m is odd, then all of the following could be odd and  [#permalink]

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19 Feb 2019, 01:10
1
B is the answer. n3 is negative as n is negative and -m3 is negative as m and m3 are positive

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If m > 0 > n and m is odd, then all of the following could be odd and  [#permalink]

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Updated on: 19 Feb 2019, 22:07
Bunuel wrote:
If m > 0 > n and m is odd, then all of the following could be odd and positive EXCEPT

A. (mn)^2

B. n^3 – m^3

C. (m – n)^2

D. m^2 + n^2

E. m(m + n)

Bunuel:
If m > 0 > n shouldn't it be m<0>n ?

Originally posted by Archit3110 on 19 Feb 2019, 04:33.
Last edited by Archit3110 on 19 Feb 2019, 22:07, edited 1 time in total.
Senior Manager
Joined: 12 Sep 2017
Posts: 308
Re: If m > 0 > n and m is odd, then all of the following could be odd and  [#permalink]

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19 Feb 2019, 08:30
N3 - M3 will be always negative.

B
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Re: If m > 0 > n and m is odd, then all of the following could be odd and  [#permalink]

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21 Feb 2019, 18:04
Bunuel wrote:
If m > 0 > n and m is odd, then all of the following could be odd and positive EXCEPT

A. (mn)^2

B. n^3 – m^3

C. (m – n)^2

D. m^2 + n^2

E. m(m + n)

Since n is negative and m is positive, we see that answer choice B has:

negative - positive; thus n^3 - m^3 will never be positive.

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Re: If m > 0 > n and m is odd, then all of the following could be odd and   [#permalink] 21 Feb 2019, 18:04
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