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alimad
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Ans e wmc

w = 15/32 ~0.4
m = 9/24 = 0.36

c = 1 - (w + m) ~ 0.24


so w m c in descending order another :oops: everything I do after 1 AM I seem to miss

ascending: c m w..
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Answer a - c, m, w

m ~ 1/3
w ~ 1/2

and m+w+c = 1 hence c ~ 1/6

Hence increasing order would be c -> m -> w
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Don't feel too bad gk3.14

I did the same thing and I don't even have an excuse :oops:
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This is Gmat Prep Question - I Ans as A ..coz that seem to make most sense and i thought i got that rite

Where did u get the Ans as E ??
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This is Gmat Prep Question - I Ans as A ..coz that seem to make most sense and i thought i got that rite

Where did u get the Ans as E ??



I did not read the question right.. *** warning*** and thought it was asking for descending.. Like I said at 1 AM .. everything seems upside down.. :beat
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If m = 9/25, w = 15/32, and m + w+ c = 1, which of the following gives the values of m, w, c in increasing order?

a.c, m, w
b.c, w, m
c.m,w,c
d.w,c,m
e.w,m,c

w is approx = half

m is approx = 0.4
thus sure

a is the answer increasing order ( c<m<w)
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Yes, decimals work faster than common denominators here. E would be correct if the question asked for DESCENDING order.
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m = 9/25 = 0.36
w = 15/32 = 0.4
On substituting C = 0.24
c , m , w
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alimad
If m = 9/25, w = 15/32, and m + w + c = 1, which of the following gives the values of m, w, and c in increasing order?

A. c, m, w
B. c, w, m
C. m, w, c
D. w, c, m
E. w, m, c

One can solve this one using 2 methods.

Method 1
- See the way PAresh did it. I've solved this the same when saw this problem in the test.

Mehod 2
\(\frac{9}{25} = \frac{54}{150}\) and \(\frac{15}{32} = \frac{75}{150}\), so \(1-\frac{54}{150}-\frac{75}{150}\), so it's evident that c<m<w

Answer A


That made the problem look so easy

Thanks
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m = 9/25 = 0.36
w = 15/32 = 0.4
On substituting C = 0.24
c , m , w on increasing order .
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Hi,

Since we are going to use a lot of percent to decimal to fraction conversion, best is to convert in to % and compare.

Well lets see how the fractions fair in terms of "%"
so "m"= \(\frac{9}{25}\) is 36%.
w= \(\frac{15}{32}\)< \(\frac{15}{30}\)

\(\frac{1}{30}\) is close to 3.33%

\(\frac{15}{32}\) is 46%

so c =100-(36+46)= 18%

19<36<45
c<m<w

Probus
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alimad
If m = 9/25, w = 15/32, and m + w + c = 1, which of the following gives the values of m, w, and c in increasing order?

A. c, m, w
B. c, w, m
C. m, w, c
D. w, c, m
E. w, m, c

Given: m = 9/25, w = 15/32, and m + w + c = 1

Asked: Which of the following gives the values of m, w, and c in increasing order?


m = 9/25 = 36%
w = 15/32 = 47% approx
m + w + c = 100%
c = 100% - (36% + 47%) = 17%

c<m<w

IMO A
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alimad
If m = 9/25, w = 15/32, and m + w + c = 1, which of the following gives the values of m, w, and c in increasing order?

A. c, m, w
B. c, w, m
C. m, w, c
D. w, c, m
E. w, m, c

We can see w = 15/32 is almost one half, and m is definitely smaller but sizable. This gives no room left for c to be greater than one half, therefore w must be the greatest. Looking at the choices we are left with A.
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[quote="PareshGmat"]m = \(\frac{9}{25}\) > which is around \(\frac{1}{3}\)

w = \(\frac{15}{32}\) > which is around \(\frac{1}{2}\)

Together m & w would constitute around \(\frac{5}{6}\), so the remaining c would be around \(\frac{1}{6}\) which is far less than m & w

Increasing order: c, m w

Answer = A
Hi Paresh,

Please explain how 15/32>1/2
15/30=0.5 and 15/32=0.46....Also, if we have the same numerator and the denominator keep on increasing that I'll make the number smaller...right?
Please help me.
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What level is this question? 600-650?
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Abhishek009
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Corinamm
What level is this question? 600-650?
Yes certainly nothing more than that in my opiinion!!!
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PareshGmat
m = \(\frac{9}{25}\) > which is around \(\frac{1}{3}\)

w = \(\frac{15}{32}\) > which is around \(\frac{1}{2}\)

Together m & w would constitute around \(\frac{5}{6}\), so the remaining c would be around \(\frac{1}{6}\) which is far less than m & w

Increasing order: c, m w

Answer = A

Bunuel, Kindly update the OA :)

Hi
Can u please explain how did u get 1/3 I also tried to simplify the expression to the lowest term but couldn't do it.
Thanks
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