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AndrewN
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ansh00700
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If m and n are integers, what is the value of \(m^4 + n^4\)?

\((1)\) \(n^3 = 27\)

\((2)\) \(m^3= –27\)


Bunuel n can be -3 or +3 , so the final answer can be 2 values why its C and not E

n^3 = 27 has only one solution because cube roots (odd powers) preserve the sign. So n = 3 is the only real solution.

n = -3 would give n^3 = -27, not 27.
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Thank you :). i was making cuber root and taking both + and negative sign . I dont know what was i thinking . Thanks a lot
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ansh00700
AndrewN
If m and n are integers, what is the value of \(m^4 + n^4\)?

\((1)\) \(n^3 = 27\)

\((2)\) \(m^3= –27\)


Bunuel n can be -3 or +3 , so the final answer can be 2 values why its C and not E

n^3 = 27 has only one solution because cube roots (odd powers) preserve the sign. So n = 3 is the only real solution.

n = -3 would give n^3 = -27, not 27.
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