sjuniv32
If \(m\) and \(n\) denote the tens’ and units’ digits of the six-digit number 763,2\(mn\). Is 763,2\(mn\) divisible by 6?
(I) \(m + n\) = 9
(II) The two-digit number \(mn\) is divisible by 4.
763,2\(mn\) will be divisible by 6, if it is divisible by both 2 and 3..
a) divisibility by 2..
the units digit or n should be even
b) divisibility by 3..
the sum of digits should be divisible by 3. So, 7+6+3+2+m+n=18+m+n or m+n should be divisible by 3
(I) \(m + n\) = 9
So 7632mn is divisible by 3, but
if m=4 and n=5, not divisible by 2
if m=5 and n=4, divisible by 2
Insuff
(II) The two-digit number \(mn\) is divisible by 4
So 7632mn is divisible by 2, but
if m=3 and n=2, not divisible by 3
if m=5 and n=4, divisible by 2
Insuff
Combined,
Statement I says 7632mn is divisible by 3
Statement II says 7632mn is divisible by 2
So, 7632mn is divisible by 6
Suff
C