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18 Feb 2022, 02:30
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D
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Difficulty:
5%
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Question Stats:
94% (00:42) correct
6%
(00:56)
wrong
based on 65
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If m is a positive integer, is m^3 an odd integer?
(1) m is an even integer.
(2) √m is an even integer.
(1) m is an even integer.
(2) √m is an even integer.
kungfury42
Joined: 07 Jan 2022
Last visit: 31 May 2023
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18 Feb 2022, 02:46
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(1) If m is even, m³ will be even and not odd. Sufficient.
(2) If √m is even, m will be be even, and thus m³ will be even and not odd. Sufficient.
Hence, D.
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(2) If √m is even, m will be be even, and thus m³ will be even and not odd. Sufficient.
Hence, D.
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18 Feb 2022, 18:40
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IMO: D
For m^3 to be odd, m needs to be odd. (Odd number raised to +ve integer will be Odd).
Statement 1:
m is an even integer.
=> m^3 will be even.
Sufficient.
Statement 2:
√m is an even integer.
=> m is even => m^3 is even.
Sufficient.
Both statements are individually sufficient.
For m^3 to be odd, m needs to be odd. (Odd number raised to +ve integer will be Odd).
Statement 1:
m is an even integer.
=> m^3 will be even.
Sufficient.
Statement 2:
√m is an even integer.
=> m is even => m^3 is even.
Sufficient.
Both statements are individually sufficient.
