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kiran120680
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bond001

I was not able to prove statement 1 false i only got three numbers that are prime
25,49,121 and square root of them is prime numbers

First, we need it to be true that √m gives us a remainder of 1 when we divide by 6. m cannot equal 25 or 121 here, because then √m would be 5 or 11, and those numbers give us a remainder of 5 when we divide by 6.

If the remainder is 1 when we divide √m by 6, then √m could be any number in this list:

1, 7, 13, 19, 25, 31, 37, 43, 49, ...

Since only some of these numbers are prime, Statement 1 is not sufficient (it might be that m = 1, or m = 625, and then √m is not prime).
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:) Thanks IanStewart got it
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