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If m is an even integer, v is an odd integer, and m > v> 0, which of
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Updated on: 07 Feb 2019, 22:53
carcass wrote: If m is an even integer, v is an odd integer, and m > v > 0, which of the following represents the number of even integers less than m and greater than v ?
A. \(\frac{mv}{2} 1\)
B. \(\frac{mv1}{2}\)
C. \(\frac{mv}{2}\)
D. \(mv1\)
E. \(mv\) Let m = 4 and v = 3 Always remember to check all the values, if in some case you find 2 options satisfying the values take another value and we should be good. 4>3>0, here the number of even integers less than m and greater than v = 0 Put back the values in the answer options We can get a zero from B and D, Now we will to test for some other value for m and v m = 8 v = 1 8>1>0, number of even integers less than m and greater than v = 3 (811)/2 = 3 D says there are 6 such values So B wins.
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Originally posted by KanishkM on 07 Feb 2019, 22:03.
Last edited by KanishkM on 07 Feb 2019, 22:53, edited 1 time in total.



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If m is an even integer, v is an odd integer, and m > v> 0, which of
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07 Feb 2019, 22:26
KanishkM wrote: carcass wrote: If m is an even integer, v is an odd integer, and m > v > 0, which of the following represents the number of even integers less than m and greater than v ?
A. \(\frac{mv}{2} 1\)
B. \(\frac{mv1}{2}\)
C. \(\frac{mv}{2}\)
D. \(mv1\)
E. \(mv\) Let m = 4 and v = 3 4>3>0, here the number of even integers less than m and greater than v = 0 Put back the values in the answer options We can get a zero from B Always remember to check all the values, if in some case you find 2 options satisfying the values take another value and we should be good. KanishkM , with those choices, we also get a zero from option D.
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Re: If m is an even integer, v is an odd integer, and m > v> 0, which of
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07 Feb 2019, 22:54
generis wrote: KanishkM wrote: carcass wrote: If m is an even integer, v is an odd integer, and m > v > 0, which of the following represents the number of even integers less than m and greater than v ?
A. \(\frac{mv}{2} 1\)
B. \(\frac{mv1}{2}\)
C. \(\frac{mv}{2}\)
D. \(mv1\)
E. \(mv\) Let m = 4 and v = 3 4>3>0, here the number of even integers less than m and greater than v = 0 Put back the values in the answer options We can get a zero from B Always remember to check all the values, if in some case you find 2 options satisfying the values take another value and we should be good. KanishkM , with those choices, we also get a zero from option D. generis, My reasoning backfired on me I truly agree on that , said that,i have done the amendments.
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If m is an even integer, v is an odd integer, and m > v> 0, which of
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07 Feb 2019, 23:06
KanishkM wrote: generis, My reasoning backfired on me I truly agree on that , said that,i have done the amendments. KanishkM  mmm, not exactly. Your reasoning is really solid —including the part in which you tell us, correctly, that we should check each option. No matter. Mistakes are how we learn.
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Re: If m is an even integer, v is an odd integer, and m > v> 0, which of
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07 Feb 2019, 23:13
generis wrote: KanishkM  mmm, not exactly. Your reasoning is really solid —including the part in which you tell us, correctly, that we should check each option. No matter. Mistakes are how we learn. generis I fully support your statement.
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Re: If m is an even integer, v is an odd integer, and m > v> 0, which of
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09 Feb 2019, 01:14
carcass wrote: If m is an even integer, v is an odd integer, and m > v > 0, which of the following represents the number of even integers less than m and greater than v ?
A. \(\frac{mv}{2} 1\)
B. \(\frac{mv1}{2}\)
C. \(\frac{mv}{2}\)
D. \(mv1\)
E. \(mv\) simply plugin m=6 and v= 3 4 ie. 1 digit even possible >3 <6 so IMO B
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Re: If m is an even integer, v is an odd integer, and m > v> 0, which of
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18 Mar 2019, 15:55
Hi here are my two cents for this questions. If this question were to be marked based on options here is how i would go about solving it . Well, Option A, C can be ruled out for following reason. \(\frac{odd}{Even}\) is never Integer and we are looking for how many even integers would there be between v and m excluding m , and Option E gives number of integers between v and m, excluding either m or v Which leaves us with choice B and D Now choice B and D both gives us integers value but look at choice D . It actually gives us number of integers between v and m excluding both . So our answer is Choice B Lets do this algebraically. if v is odd, then v+1 will be even . and if m is even So we have number of integers between m and v+1 excluding one of the ends is = \(\frac{mv1}{2}\) So we do have a formula for such type of questions If we are counting in steps of x , from \(n_1\) to \(n_z\) including both end points we get \(\frac{n_z  n_1}{x}\) +1 If we are counting in steps of x , from \(n_1\) to \(n_z\) including only one end points we get \(\frac{n_z  n_1}{x}\) If we are counting in steps of x , from \(n_1\) to \(n_z\) excluding both end points we get \(\frac{n_z  n_1}{x}\) 1
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Re: If m is an even integer, v is an odd integer, and m > v> 0, which of
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