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08 Jan 2017, 08:06
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
47% (01:30) correct
53%
(01:48)
wrong
based on 80
sessions
History
Date
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Result
Not Attempted Yet
If m, n and p are distinct digits and their product is another distinct digit, what is value of the product mnp?
(1) mn = 8
(2) m is twice n and n is twice p
(1) mn = 8
(2) m is twice n and n is twice p
Bunuel
(1) we dont know value p
insuff..
(2) m=2n && n=2p
thus m= 4p
mnp= m*m/2*m/4==M^3/8
m could be 2 or -2 again not suff..
Combining from (1) mn=8 and from (2) m=2n
thus m*m/2=8 or m^2=16
thus m=4 , -4
so mnp = m^3/8 = 4*4*4/8 = 8(when m=4)
&& m^3/8 = -4*-4*-4/8 = -8(when m=-4)
thus mnp= 8 , -8
NOt suff
Ans E
Updated on: 08 Jan 2017, 12:57
Originally posted by vitaliyGMAT on 08 Jan 2017, 10:36.
Last edited by vitaliyGMAT on 08 Jan 2017, 12:57, edited 1 time in total.
Last edited by vitaliyGMAT on 08 Jan 2017, 12:57, edited 1 time in total.
Kudos
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Bunuel
p≠0. Otherwise the product will also be 0.
(1) mn=8
1*8*p and 8*1*p give us p=0 and we need to discard this option.
2*4*p and 4*2*p give us p = 1. Sufficient.
(2) \(m*n*p = 4p*2p*p = 8*p^3\)
Only awailable option is p=1. Sufficient.
Answer D
