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Bunuel
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I think the answer is E

If m, n and p are nonzero digits and mn = p. What is p?
(1) n < m

This statement is insufficient as m can take any value i.e. 9,8,7,6,5,4,3,2.
Therefore, N can have 8,7,6,5,4,3,2,1
.
(2) m = 5
We just have m=5 ;
No restraint on n. it could be 1,2,3,4,5,6,7,8,9
So, statement 2 is also Insufficient.

Combining Statement 1 & 2
m can take only value as 5, but n can be 1,2,3 or 4
So, p can have more than one option
So, combining the statements also insufficient
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I am not completely sure but I think it should be (B)

If m, n and p are nonzero digits and mn = p. What is p?

It has been mentioned that m,n,p are non zero digits and NOT numbers. Hence, assuming they are single digits.

(1) n < m
Example : 1*2/ 2*3
(A) is not sufficient

(2) m = 5
When we know that m=5, the only possibility that remains is that of n=1 since that is the only combination that will result in p as a non zero DIGIT.
(B) is sufficient.

Like I said, I have solved as per my understanding of the question. Will wait for the OE.
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If m, n and p are nonzero digits and mn = p. What is p?

(1) n < m
No information about p
Not sufficient

(2) m = 5
No information about n
Not sufficient

(1) + (2)

For m=5, n=4, p will be 20
For m=5, n=3, p will be 15

Not sufficient.

Choice E

Posted from my mobile device
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Could someone please answer how in the question we are assuming all are single digit numbers ?
Thanks
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Jyotiraditya89
Could someone please answer how in the question we are assuming all are single digit numbers ?
Thanks

Check the highlighted part:

    If m, n and p are nonzero digits and mn = p. What is p?

Nonzero digits are 1, 2, 3, 4, 5, 6, 7, 8, and 9.
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